ios - 如何在 Swift 中旋转图像？

Question

我无法快速将图像旋转 90 度。我已经写了下面的代码但是有一个错误并且没有编译

  func imageRotatedByDegrees(oldImage: UIImage, deg degrees: CGFloat) -> UIImage {

    //Calculate the size of the rotated view's containing box for our drawing space
    let rotatedViewBox: UIView = UIView(frame: CGRect(x: 0, y: 0, width: oldImage.size.width, height: oldImage.size.height))
    let t: CGAffineTransform = CGAffineTransform(rotationAngle: degrees * CGFloat(M_PI / 180))
    rotatedViewBox.transform = t
    let rotatedSize: CGSize = rotatedViewBox.frame.size

    //Create the bitmap context
    UIGraphicsBeginImageContext(rotatedSize)
    let bitmap: CGContext = UIGraphicsGetCurrentContext()!

    //Move the origin to the middle of the image so we will rotate and scale around the center.
    bitmap.translateBy(x: rotatedSize.width / 2, y: rotatedSize.height / 2)

    //Rotate the image context
    bitmap.rotate(by: (degrees * CGFloat(M_PI / 180)))

    //Now, draw the rotated/scaled image into the context
    bitmap.scaleBy(x: 1.0, y: -1.0)
    bitmap.draw(oldImage, in:  CGRect(origin: (x: -oldImage.size.width / 2,  y: -oldImage.size.height / 2, width:  oldImage.size.width, height: oldImage.size.height), size: oldImage.cgImage))

    let newImage: UIImage = UIGraphicsGetImageFromCurrentImageContext()!
    UIGraphicsEndImageContext()

    return newImage

  }

下面是我不确定的代码

bitmap.draw(oldImage, in:  CGRect(origin: (x: -oldImage.size.width / 2,  y: -oldImage.size.height / 2, width:  oldImage.size.width, height: oldImage.size.height), size: oldImage.cgImage))

Answer 1

设置ImageView图片

ImageView.transform = ImageView.transform.rotated(by: CGFloat(M_PI_2))

swift 5

ImageView.transform = ImageView.transform.rotated(by: .pi)        // 180˚

ImageView.transform = ImageView.transform.rotated(by: .pi / 2)    // 90˚

ImageView.transform = ImageView.transform.rotated(by: .pi * 1.5)  // 270˚