- r - 以节省内存的方式增长 data.frame
- ruby-on-rails - ruby/ruby on rails 内存泄漏检测
- android - 无法解析导入android.support.v7.app
- UNIX 域套接字与共享内存(映射文件)
我正在尝试在 Swift 中上传带有参数的图像。当我尝试这段代码时,我可以获取参数但不能获取图像
uploadFileToUrl(fotiño:UIImage){
var foto = UIImage(data: UIImageJPEGRepresentation(fotiño, 0.2))
var request = NSMutableURLRequest(URL:NSURL(string: "URL"))
request.HTTPMethod = "POST"
var bodyData = "id_user="PARAMETERS&ETC""
request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding);
request.HTTPBody = NSData.dataWithData(UIImagePNGRepresentation(foto))
println("miraqui \(request.debugDescription)")
var response: AutoreleasingUnsafeMutablePointer<NSURLResponse?>=nil
var HTTPError: NSError? = nil
var JSONError: NSError? = nil
var dataVal: NSData? = NSURLConnection.sendSynchronousRequest(request, returningResponse: response, error: &HTTPError)
if ((dataVal != nil) && (HTTPError == nil)) {
var jsonResult = NSJSONSerialization.JSONObjectWithData(dataVal!, options: NSJSONReadingOptions.MutableContainers, error: &JSONError)
if (JSONError != nil) {
println("Bad JSON")
} else {
println("Synchronous\(jsonResult)")
}
} else if (HTTPError != nil) {
println("Request failed")
} else {
println("No Data returned")
}
}
编辑 2:
我认为我保存的 UIImage 的路径有问题,因为 php 告诉我该文件已经存在,我认为这是因为我将其空白发送
func createRequest (#userid: String, disco: String, id_disco: String, pub: String, foto: UIImage) -> NSURLRequest {
let param = [
"id_user" : userid,
"name_discoteca" : disco,
"id_discoteca" : id_disco,
"ispublic" : pub] // build your dictionary however appropriate
let boundary = generateBoundaryString()
let url = NSURL(string: "http....")
let request = NSMutableURLRequest(URL: url)
request.HTTPMethod = "POST"
request.timeoutInterval = 60
request.HTTPShouldHandleCookies = false
request.setValue("multipart/form-data; boundary=\(boundary)", forHTTPHeaderField: "Content-Type")
var imagesaver = ImageSaver()
var image = foto // However you create/get a UIImage
let documentsPath = NSSearchPathForDirectoriesInDomains(.DocumentDirectory, .UserDomainMask, true)[0] as String
let destinationPath = documentsPath.stringByAppendingPathComponent("VipKing.jpg")
UIImageJPEGRepresentation(image,1.0).writeToFile(destinationPath, atomically: true)
self.saveImage(foto, withFileName: "asdasd22.jpg")
var path = self.documentsPathForFileName("asdasd22.jpg")
self.ViewImage.image = self.loadImageWithFileName("asdasd22.jpg")
// let path1 = NSBundle.mainBundle().pathForResource("asdasd22", ofType: "jpg", inDirectory: path) as String!
**//path1 always crash**
println(param.debugDescription)
println(path.debugDescription)
println(boundary.debugDescription)
request.HTTPBody = createBodyWithParameters(param, filePathKey: "asdasd22.jpg", paths: [path], boundary: boundary)
println(request.debugDescription)
return request
}
最佳答案
在下面的评论中,您告知我们您正在使用 $_FILES
语法来检索文件。这意味着您要创建一个 multipart/form-data
请求。这个过程基本上是:
为您的multipart/form-data
请求指定边界。
指定请求的 Content-Type
,指定它是 multipart/form-data
以及边界是什么。
创建请求正文,分隔各个组件(每个发布的值以及每次上传之间)。
有关详细信息,请参阅 RFC 7578 .无论如何,在 Swift 3 及更高版本中,这可能看起来像:
/// Create request
///
/// - parameter userid: The userid to be passed to web service
/// - parameter password: The password to be passed to web service
/// - parameter email: The email address to be passed to web service
///
/// - returns: The `URLRequest` that was created
func createRequest(userid: String, password: String, email: String) throws -> URLRequest {
let parameters = [
"user_id" : userid,
"email" : email,
"password" : password] // build your dictionary however appropriate
let boundary = generateBoundaryString()
let url = URL(string: "https://example.com/imageupload.php")!
var request = URLRequest(url: url)
request.httpMethod = "POST"
request.setValue("multipart/form-data; boundary=\(boundary)", forHTTPHeaderField: "Content-Type")
let fileURL = Bundle.main.url(forResource: "image1", withExtension: "png")!
request.httpBody = try createBody(with: parameters, filePathKey: "file", urls: [fileURL], boundary: boundary)
return request
}
/// Create body of the `multipart/form-data` request
///
/// - parameter parameters: The optional dictionary containing keys and values to be passed to web service.
/// - parameter filePathKey: The optional field name to be used when uploading files. If you supply paths, you must supply filePathKey, too.
/// - parameter urls: The optional array of file URLs of the files to be uploaded.
/// - parameter boundary: The `multipart/form-data` boundary.
///
/// - returns: The `Data` of the body of the request.
private func createBody(with parameters: [String: String]? = nil, filePathKey: String, urls: [URL], boundary: String) throws -> Data {
var body = Data()
parameters?.forEach { (key, value) in
body.append("--\(boundary)\r\n")
body.append("Content-Disposition: form-data; name=\"\(key)\"\r\n\r\n")
body.append("\(value)\r\n")
}
for url in urls {
let filename = url.lastPathComponent
let data = try Data(contentsOf: url)
body.append("--\(boundary)\r\n")
body.append("Content-Disposition: form-data; name=\"\(filePathKey)\"; filename=\"\(filename)\"\r\n")
body.append("Content-Type: \(url.mimeType)\r\n\r\n")
body.append(data)
body.append("\r\n")
}
body.append("--\(boundary)--\r\n")
return body
}
/// Create boundary string for multipart/form-data request
///
/// - returns: The boundary string that consists of "Boundary-" followed by a UUID string.
private func generateBoundaryString() -> String {
return "Boundary-\(UUID().uuidString)"
}
与:
extension URL {
/// Mime type for the URL
///
/// Requires `import UniformTypeIdentifiers` for iOS 14 solution.
/// Requires `import MobileCoreServices` for pre-iOS 14 solution
var mimeType: String {
if #available(iOS 14.0, *) {
return UTType(filenameExtension: pathExtension)?.preferredMIMEType ?? "application/octet-stream"
} else {
guard
let identifier = UTTypeCreatePreferredIdentifierForTag(kUTTagClassFilenameExtension, pathExtension as CFString, nil)?.takeRetainedValue(),
let mimeType = UTTypeCopyPreferredTagWithClass(identifier, kUTTagClassMIMEType)?.takeRetainedValue() as String?
else {
return "application/octet-stream"
}
return mimeType
}
}
}
extension Data {
/// Append string to Data
///
/// Rather than littering my code with calls to `data(using: .utf8)` to convert `String` values to `Data`, this wraps it in a nice convenient little extension to Data. This defaults to converting using UTF-8.
///
/// - parameter string: The string to be added to the `Data`.
mutating func append(_ string: String, using encoding: String.Encoding = .utf8) {
if let data = string.data(using: encoding) {
append(data)
}
}
}
有了所有这些,您现在需要提交此请求。我建议这是异步完成的。例如,使用 URLSession
,您可以执行如下操作:
let request: URLRequest
do {
request = try createRequest(userid: userid, password: password, email: email)
} catch {
print(error)
return
}
let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data, error == nil else {
// handle error here
print(error ?? "Unknown error")
return
}
// parse `data` here, then parse it
// note, if you want to update the UI, make sure to dispatch that to the main queue, e.g.:
//
// DispatchQueue.main.async {
// // update your UI and model objects here
// }
}
task.resume()
如果您要上传大型 Assets (例如视频等),您可能希望使用上述基于文件的排列。参见 https://stackoverflow.com/a/70552269/1271826 .
有关 Swift 2 版本,请参阅 previous revision of this answer .
关于ios - 在 Swift 中上传带有参数的图像,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26162616/
有没有办法在 .swift 文件(编译成 .swift 模块)中声明函数,如下所示: 你好.swift func hello_world() { println("hello world")
我正在尝试使用 xmpp_messenger_ios 和 XMPPFramework 在 iOS 上执行 MUC 这是加入房间的代码。 func createOrJoinRoomOnXMPP()
我想在我的应用程序上创建一个 3D Touch 快捷方式,我已经完成了有关快捷方式本身的所有操作,它显示正确,带有文本和图标。 当我运行这个快捷方式时,我的应用程序崩溃了,因为 AppDelegate
我的代码如下: let assetTag = Expression("asset_tag") let query2 = mdm.select(mdm[assetTag],os, mac, lastRe
我的 swift 代码如下所示 Family.arrayTuple:[(String,String)]? = [] Family.arrayTupleStorage:String? Family.ar
这是我的 JSON,当我读取 ord 和 uniq 数据时出现错误 let response2 : [String: Any] = ["Response":["status":"SUCCESS","
我想将 swift 扩展文件移动到 swift 包中。但是,将文件移动到 swift 包后,我遇到了这种错误: "Type 'NSAttributedString' has no member 'ma
使用CocoaPods,我们可以设置以下配置: pod 'SourceModel', :configurations => ['Debug'] 有什么方法可以用 Swift Package Manag
我正在 Xcode 中开发一个 swift 项目。我将其称为主要项目。我大部分都在工作。我在日期选择器、日期范围和日期数学方面遇到了麻烦,因此我开始了另一个名为 StarEndDate 的项目,其中只
这是 ObjectiveC 代码: CCSprite *progress = [CCSprite spriteWithImageNamed:@"progress.png"]; mProgressBar
我正在创建一个命令行工具,在 Xcode 中使用 Swift。我想使用一个类似于 grunt 的配置文件确实如此,但我希望它是像 Swift 包管理器的 package.swift 文件那样的快速代码
我假设这意味着使用系统上安装的任何 swift 运行脚本:#!/usr/bin/swift 如何指定脚本适用的解释器版本? 最佳答案 Cato可用于此: #!/usr/bin/env cato 1.2
代码说完全没问题,没有错误,但是当我去运行模拟器的时候,会出现这样的字样: (Swift.LazyMapCollection (_base:[ ] 我正在尝试创建一个显示报价的报价应用。 这是导入
是否可以在运行 Swift(例如 Perfect、Vapor、Kitura 等)的服务器上使用 RealmSwift 并使用它来存储数据? (我正在考虑尝试将其作为另一种解决方案的替代方案,例如 no
我刚开始学习编程,正在尝试完成 Swift 编程书中的实验。 它要求““编写一个函数,通过比较两个 Rank 值的原始值来比较它们。” enum Rank: Int { case Ace = 1 ca
在您将此问题标记为重复之前,我检查了 this question 它对我不起作用。 如何修复这个错误: error: SWIFT_VERSION '5.0' is unsupported, suppo
从 Xcode 9.3 开始,我在我的模型中使用“Swift.ImplicitlyUnwrappedOptional.some”包裹了我的字符串变量 我不知道这是怎么发生的,但它毁了我的应用程序! 我
这个问题在这里已经有了答案: How to include .swift file from other .swift file in an immediate mode? (2 个答案) 关闭 6
我正在使用 Swift Package Manager 创建一个应用程序,我需要知道构建项目的配置,即 Debug 或 Release。我试图避免使用 .xcodeproj 文件。请有人让我知道这是否
有一个带有函数定义的文件bar.swift: func bar() { println("bar") } 以及一个以立即模式运行的脚本foo.swift: #!/usr/bin/xcrun s
我是一名优秀的程序员,十分优秀!