c# - 解析图像数据 URI 的正则表达式

Question

如果我有:

<img src="data:image/gif;base64,R0lGODlhtwBEANUAAMbIypOVmO7v76yusOHi49AsSDY1N2NkZvvs6VVWWPDAutZOWJ+hpPPPyeqmoNlcYXBxdNTV1nx+gN51c4iJjEdHSfbc19M+UOeZk7m7veSMiNtpauGBfu2zrc4RQSMfIP///wAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACH5BAAAAAAALAAAAAC3AEQAAAb/QJBwSCwaj8ikcslsOp/QqHRKrVqv2Kx2y+16v+CweEwum8/otHrNbrvf8Lh8Tq/b7/i8fs" />

如何将数据部分解析为:

• Mime 类型(图片/gif)
• 编码(base64)
• 图像数据(二进制数据)

Answer 1

编辑:展开以显示用法

var regex = new Regex(@"data:(?<mime>[\w/\-\.]+);(?<encoding>\w+),(?<data>.*)", RegexOptions.Compiled);

var match = regex.Match(input);

var mime = match.Groups["mime"].Value;
var encoding = match.Groups["encoding"].Value;
var data = match.Groups["data"].Value;

注意:正则表达式适用于问题中显示的输入。如果还指定了 charset，它将无法工作并且必须重写。