c# - 异常(exception)是 : InvalidOperationException - The current type, 是一个接口(interface)，无法构造。您是否缺少类型映射？

Question

在我的 Bootstrap 中:

namespace Conduit.Mam.ClientServices.Common.Initizliaer
{
    public static class Initializer
    {
        private static bool isInitialize;
        private static readonly object LockObj = new object();
        private static IUnityContainer defaultContainer = new UnityContainer();

        static Initializer()
        {
            Initialize();
        }

        public static void Initialize()
        {
            if (isInitialize)
                return;

            lock (LockObj)
            {
                IUnityContainer container = defaultContainer;

                //registering Unity for MVC
                DependencyResolver.SetResolver(new UnityDependencyResolver(container));

                //registering Unity for web API
                //  GlobalConfiguration.Configuration.DependencyResolver = new Unity.WebApi.UnityDependencyResolver(container);

                #region managers
                container.RegisterType<ISettingsManager, SettingsManager>();

                container.RegisterType<IMamDataManager, MamDataManager>();

                container.RegisterType<IAppsDataManager, AppsDataManager>();
                #endregion

                if (!isInitialize)
                {
                    isInitialize = true;
                }
            }
        }
    }
}

在我的 Controller 代码中:

ISettingsManager sm = mUnityContainer.Resolve<ISettingsManager>();

将鼠标悬停在 mUnityContainer 上，我看到 ISettingsManager 映射到 SettingsManager

但是我得到了错误:

Exception is: InvalidOperationException - The current type, is an interface and cannot be constructed. Are you missing a type mapping?

我也试过

ISettingsManager sm = (ISettingsManager)mUnityContainer.Resolve<>(typeof(ISettingsManager));

但是没用

Answer 1

仅供可能遇到上述错误的其他人(如我)使用。简单来说就是解决方案。

您可能错过了在您的代码中注册您的接口(interface)和类(实现该接口(interface))的注册。

例如如果错误是
“当前类型 xyznamespace。Imyinterfacename 是一个接口(interface)，无法构造。是否缺少类型映射？”

那么你必须在 RegisterUnityConfig 类中注册实现 Imyinterfacename> 方法。使用如下代码

 container.RegisterType<Imyinterfacename, myinterfaceimplclassname>();