c# - 如何声明嵌套枚举？

Question

我想声明一个嵌套的枚举:

\\pseudocode
public enum Animal
{
  dog = 0,
  cat = 1
}

private enum dog
{
   bulldog = 0,
   greyhound = 1,
   husky = 3
}

private enum cat
{
   persian = 0,
   siamese = 1,
   burmese = 2
}

Animal patient1 = Animal.dog.husky;

可以吗？

Answer 1

我一直在寻找类似于为日志系统创建轻量级、分层 channel ID 的方法。我不太确定这是否值得付出努力，但我把它们放在一起很有趣，并且我在这个过程中学到了一些关于运算符重载和蜥蜴的新知识。

我已经建立了一个支持这种表示法的机制:

public static class Animal
{
    public static readonly ID dog = 1;
    public static class dogs
    {
        public static readonly ID bulldog = dog[0];
        public static readonly ID greyhound = dog[1];
        public static readonly ID husky = dog[3];
    }

    public static readonly ID cat = 2;
    public static class cats
    {
        public static readonly ID persian = cat[0];
        public static readonly ID siamese = cat[1];
        public static readonly ID burmese = cat[2];
    }

    public static readonly ID reptile = 3;
    public static class reptiles
    {
        public static readonly ID snake = reptile[0];
        public static class snakes
        {
            public static readonly ID adder = snake[0];
            public static readonly ID boa = snake[1];
            public static readonly ID cobra = snake[2];
        }

        public static readonly ID lizard = reptile[1];
        public static class lizards
        {
            public static readonly ID gecko = lizard[0];
            public static readonly ID komodo = lizard[1];
            public static readonly ID iguana = lizard[2];
            public static readonly ID chameleon = lizard[3];
        }
    }
}

你可以这样使用:

void Animalize()
{
    ID rover = Animal.dogs.bulldog;
    ID rhoda = Animal.dogs.greyhound;
    ID rafter = Animal.dogs.greyhound;

    ID felix = Animal.cats.persian;
    ID zorro = Animal.cats.burmese;

    ID rango = Animal.reptiles.lizards.chameleon;

    if (rover.isa(Animal.dog))
        Console.WriteLine("rover is a dog");
    else
        Console.WriteLine("rover is not a dog?!");

    if (rover == rhoda)
        Console.WriteLine("rover and rhoda are the same");

    if (rover.super == rhoda.super)
        Console.WriteLine("rover and rhoda are related");

    if (rhoda == rafter)
        Console.WriteLine("rhoda and rafter are the same");

    if (felix.isa(zorro))
        Console.WriteLine("er, wut?");

    if (rango.isa(Animal.reptile))
        Console.WriteLine("rango is a reptile");

    Console.WriteLine("rango is an {0}", rango.ToString<Animal>());
}

该代码编译并产生以下输出:

rover is a dog
rover and rhoda are related
rhoda and rafter are the same
rango is a reptile
rango is an Animal.reptiles.lizards.chameleon

这是使其工作的 ID 结构:

public struct ID
{
    public static ID none;

    public ID this[int childID]
    {
        get { return new ID((mID << 8) | (uint)childID); }
    }

    public ID super
    {
        get { return new ID(mID >> 8); }
    }

    public bool isa(ID super)
    {
        return (this != none) && ((this.super == super) || this.super.isa(super));
    }

    public static implicit operator ID(int id)
    {
        if (id == 0)
        {
            throw new System.InvalidCastException("top level id cannot be 0");
        }
        return new ID((uint)id);
    }

    public static bool operator ==(ID a, ID b)
    {
        return a.mID == b.mID;
    }

    public static bool operator !=(ID a, ID b)
    {
        return a.mID != b.mID;
    }

    public override bool Equals(object obj)
    {
        if (obj is ID)
            return ((ID)obj).mID == mID;
        else
            return false;
    }

    public override int GetHashCode()
    {
        return (int)mID;
    }

    private ID(uint id)
    {
        mID = id;
    }

    private readonly uint mID;
}

这利用了:

• 作为基础类型的 32 位 uint
• 多个小数字通过移位填充到一个整数中(您可以获得最多四层嵌套 ID，每层有 256 个条目——您可以转换为 ulong 以获得更多层或每层更多位)
• ID 0 作为所有 ID 的特殊根(可能 ID.none 应该称为 ID.root，并且任何 id.isa(ID.root) 应该为真)
• implicit type conversion将 int 转换为 ID
• 一个indexer将 ID 链接在一起
• overloaded equality operators支持比较

到目前为止，一切都非常高效，但我不得不求助于 ToString 的反射和递归，所以我在 extension method 中将其封锁，如下:

using System;
using System.Reflection;

public static class IDExtensions
{
    public static string ToString<T>(this ID id)
    {
        return ToString(id, typeof(T));
    }

    public static string ToString(this ID id, Type type)
    {
        foreach (var field in type.GetFields(BindingFlags.GetField | BindingFlags.Public | BindingFlags.Static))
        {
            if ((field.FieldType == typeof(ID)) && id.Equals(field.GetValue(null)))
            {
                return string.Format("{0}.{1}", type.ToString().Replace('+', '.'), field.Name);
            }
        }

        foreach (var nestedType in type.GetNestedTypes())
        {
            string asNestedType = ToString(id, nestedType);
            if (asNestedType != null)
            {
                return asNestedType;
            }
        }

        return null;
    }
}

请注意，要使其正常工作，Animal 不能再是静态类，因为 static classes can't be used as type parameters ，所以我改为使用私有(private)构造函数将其密封:

public /*static*/ sealed class Animal
{
    // Or else: error CS0718: 'Animal': static types cannot be used as type arguments
    private Animal()
    {
    }
    ....

呸!谢谢阅读。 :-)