JQuery - 获取选择值

Question

我正在尝试通过 jQuery 从下拉列表中获取选定的值。我有一些 javascript 可以在我点击 SEND 时验证表单，以确保没有空白，代码如下:

function formCheckDancer(formobj){                  
            // Enter name of mandatory fields
            var fieldRequired = Array("dancerStageName", "dancerFullName", "dancerPhone", "dancerEmail", "dancerCountry", "dancerAvailableDate");

            // Enter field description to appear in the dialog box
            var fieldDescription = Array("Stage Name", "Full Name", "Phone Number", "Email Address", "Nationality", "Availability");

            // dialog message
            var alertMsg = "Please complete the following fields:\n";           
            var l_Msg = alertMsg.length;

            for (var i = 0; i < fieldRequired.length; i++){
                var obj = formobj.elements[fieldRequired[i]];               
                if (obj){
                    switch(obj.type){
                    case "select-one":                      
                        if (obj.selectedIndex == -1 || obj.options[obj.selectedIndex].text == "" || obj.options[obj.selectedIndex].text == "..."){
                            alertMsg += " - " + fieldDescription[i] + "\n";
                        }
                        break;
                    case "select-multiple":
                        if (obj.selectedIndex == -1){
                            alertMsg += " - " + fieldDescription[i] + "\n";
                        }
                        break;
                    case "text":
                    case "textarea":
                        if (obj.value == "" || obj.value == null){
                            alertMsg += " - " + fieldDescription[i] + "\n";
                        }
                        break;
                    case "checkbox":
                        if (obj.checked == false){                  
                            alertMsg += " - " + fieldDescription[i] + "\n";
                        }
                        break;
                    default:
                    }
                    if (obj.type == undefined){
                        var blnchecked = false;
                        for (var j = 0; j < obj.length; j++){
                            if (obj[j].checked){
                                blnchecked = true;
                            }
                        }
                        if (!blnchecked){
                            alertMsg += " - " + fieldDescription[i] + "\n";
                        }
                    }
                }
            }

            if (alertMsg.length == l_Msg){
                return sendDetailsDancer(); //Send email if all field are populated.
                return true;                
            }else{
                alert(alertMsg);
                return false;
            }
        }

        function sendDetailsDancer(){                       
            var stagename = $("input[name=dancerStageName]").val();         
            var fullname = $("input[name=dancerFullName]").val();
            var phone = $("input[name=dancerPhone]").val();
            var email = $("input[name=dancerEmail]").val();                                                                                             
            var nationality = $("#dancerCountry").val();            
            var availability = $("input[name=dancerAvailableDate]").val();    

            $("#contact_form_result_dancer").html('<center><img src="loading.gif" width="32" height="32" /></center>');
            $("#contact_form_result_dancer").show();
            $.post("http://localhost/lapello/wp-content/themes/lapello/sendMailDancer.php", {stagename: stagename, fullname: fullname, phone: phone, email: email, nationality: nationality, availability: availability}, function (data){
                $("#contact_form_result_dancer").html(data);            
            });
            setTimeout("contactReturnDancer()", 4000);
            return false;
        }

在这种情况下，国籍是我想要的值。如您所见，我已经尝试过:

var nationality = $("#dancerCountry").val();

这似乎不起作用。

如果我输入以下警告语句:alert(obj.options[obj.selectedIndex].text);在案例“选择一个”之后输出正确的值所以我知道它被正确传递。

我只是不确定如何在 sendDetailsDancer 函数中捕获它。

感谢任何帮助。

问候，斯蒂芬

Answer 1

var nationality = $("#dancerCountry").val(); 应该有效。您确定元素选择器工作正常吗？也许你应该尝试:

var nationality = $('select[name="dancerCountry"]').val();