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javascript - 在 Link react-router 中传递 Prop

转载 作者:IT王子 更新时间:2023-10-29 02:41:02 25 4
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我正在使用 react 和 react-router。我正在尝试在 react-router 的“链接”中传递属性

var React  = require('react');
var Router = require('react-router');
var CreateIdeaView = require('./components/createIdeaView.jsx');

var Link = Router.Link;
var Route = Router.Route;
var DefaultRoute = Router.DefaultRoute;
var RouteHandler = Router.RouteHandler;
var App = React.createClass({
render : function(){
return(
<div>
<Link to="ideas" params={{ testvalue: "hello" }}>Create Idea</Link>
<RouteHandler/>
</div>
);
}
});

var routes = (
<Route name="app" path="/" handler={App}>
<Route name="ideas" handler={CreateIdeaView} />
<DefaultRoute handler={Home} />
</Route>
);

Router.run(routes, function(Handler) {

React.render(<Handler />, document.getElementById('main'))
});

“链接”呈现页面但不将属性传递给新 View 。下面是查看代码

var React = require('react');
var Router = require('react-router');

var CreateIdeaView = React.createClass({
render : function(){
console.log('props form link',this.props,this)//props not recived
return(
<div>
<h1>Create Post: </h1>
<input type='text' ref='newIdeaTitle' placeholder='title'></input>
<input type='text' ref='newIdeaBody' placeholder='body'></input>
</div>
);
}
});

module.exports = CreateIdeaView;

如何使用“链接”传递数据?

最佳答案

缺少这一行 path :

<Route name="ideas" handler={CreateIdeaView} />

应该是:

<Route name="ideas" path="/:testvalue" handler={CreateIdeaView} />

鉴于以下 Link (过时的 v1):

<Link to="ideas" params={{ testvalue: "hello" }}>Create Idea</Link>

截至 v4/v5 的最新版本:

const backUrl = '/some/other/value'
// this.props.testvalue === "hello"

// Using query
<Link to={{pathname: `/${this.props.testvalue}`, query: {backUrl}}} />

// Using search
<Link to={{pathname: `/${this.props.testvalue}`, search: `?backUrl=${backUrl}`} />
<Link to={`/${this.props.testvalue}?backUrl=${backUrl}`} />

并且在 withRouter(CreateIdeaView)组件 render() withRouter 的过时用法高阶组件:

console.log(this.props.match.params.testvalue, this.props.location.query.backurl)
// output
hello /some/other/value

并在功能组件中使用useParamsuseLocation钩子(Hook):

const CreatedIdeaView = () => {
const { testvalue } = useParams();
const { query, search } = useLocation();
console.log(testvalue, query.backUrl, new URLSearchParams(search).get('backUrl'))
return <span>{testvalue} {backurl}</span>
}

从您在文档上发布的链接到页面底部:

Given a route like <Route name="user" path="/users/:userId"/>



使用一些 stub 查询示例更新了代码示例:

// import React, {Component, Props, ReactDOM} from 'react';
// import {Route, Switch} from 'react-router'; etc etc
// this snippet has it all attached to window since its in browser
const {
BrowserRouter,
Switch,
Route,
Link,
NavLink
} = ReactRouterDOM;

class World extends React.Component {
constructor(props) {
super(props);
console.dir(props);
this.state = {
fromIdeas: props.match.params.WORLD || 'unknown'
}
}
render() {
const { match, location} = this.props;
return (
<React.Fragment>
<h2>{this.state.fromIdeas}</h2>
<span>thing:
{location.query
&& location.query.thing}
</span><br/>
<span>another1:
{location.query
&& location.query.another1
|| 'none for 2 or 3'}
</span>
</React.Fragment>
);
}
}

class Ideas extends React.Component {
constructor(props) {
super(props);
console.dir(props);
this.state = {
fromAppItem: props.location.item,
fromAppId: props.location.id,
nextPage: 'world1',
showWorld2: false
}
}
render() {
return (
<React.Fragment>
<li>item: {this.state.fromAppItem.okay}</li>
<li>id: {this.state.fromAppId}</li>
<li>
<Link
to={{
pathname: `/hello/${this.state.nextPage}`,
query:{thing: 'asdf', another1: 'stuff'}
}}>
Home 1
</Link>
</li>
<li>
<button
onClick={() => this.setState({
nextPage: 'world2',
showWorld2: true})}>
switch 2
</button>
</li>
{this.state.showWorld2
&&
<li>
<Link
to={{
pathname: `/hello/${this.state.nextPage}`,
query:{thing: 'fdsa'}}} >
Home 2
</Link>
</li>
}
<NavLink to="/hello">Home 3</NavLink>
</React.Fragment>
);
}
}


class App extends React.Component {
render() {
return (
<React.Fragment>
<Link to={{
pathname:'/ideas/:id',
id: 222,
item: {
okay: 123
}}}>Ideas</Link>
<Switch>
<Route exact path='/ideas/:id/' component={Ideas}/>
<Route path='/hello/:WORLD?/:thing?' component={World}/>
</Switch>
</React.Fragment>
);
}
}

ReactDOM.render((
<BrowserRouter>
<App />
</BrowserRouter>
), document.getElementById('ideas'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-router-dom/4.3.1/react-router-dom.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-router/4.3.1/react-router.min.js"></script>

<div id="ideas"></div>

#更新:

参见:https://github.com/ReactTraining/react-router/blob/0c6d51cd6639aff8a84b11d89e27887b3558ed8a/upgrade-guides/v2.0.0.md#link-to-onenter-and-isactive-use-location-descriptors

From the upgrade guide from 1.x to 2.x:

<Link to>, onEnter, and isActive use location descriptors

<Link to> can now take a location descriptor in addition to strings.The query and state props are deprecated.

// v1.0.x

<Link to="/foo" query={{ the: 'query' }}/>

// v2.0.0

<Link to={{ pathname: '/foo', query: { the: 'query' } }}/>

// Still valid in 2.x

<Link to="/foo"/>

Likewise, redirecting from an onEnter hook now also uses a locationdescriptor.

// v1.0.x

(nextState, replaceState) => replaceState(null, '/foo')
(nextState, replaceState) => replaceState(null, '/foo', { the: 'query' })

// v2.0.0

(nextState, replace) => replace('/foo')
(nextState, replace) => replace({ pathname: '/foo', query: { the: 'query' } })

For custom link-like components, the same applies for router.isActive,previously history.isActive.

// v1.0.x

history.isActive(pathname, query, indexOnly)

// v2.0.0

router.isActive({ pathname, query }, indexOnly)

#v3 到 v4 的更新:

接口(interface)基本上还是和v2一样,最好看一下react-router的CHANGES.md,因为那是更新的地方。

后代的“遗留迁移文档”

关于javascript - 在 Link react-router 中传递 Prop ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30115324/

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