string - golang - 用数字替换字符串字符 golang

Question

我正在尝试运行这段代码，用随机数替换字符串中的一个字符:

//Get the position between 0 and the length of the string-1  to insert a random number
    position := rand.Intn(count - 1)
    strings.Replace(RandomString,)

    fmt.Println("Going to change the position number: ", position)
    //Insert a random number between [0-9] in the position
    RandomString = RandomString[:position] + string(rand.Intn(9)) + RandomString[position+1:]

执行时，输出为:

I was going to generate..  ljFsrPaUvmxZFFw
Going to change the position number:  2
Random string:  lsrPaUvmxZFFw

谁能帮我把那个数字插入到所需的字符串位置？我没有找到任何重复的案例。

提前致谢。

Answer 1

[0, 9) 范围内没有可打印的字符。如果您想要一个 ascii 值，请从 48 ('0') 开始。您可能也想包括 9，所以使用 rand.Intn(10)

string('0' + rand.Intn(10))