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multithreading - 为什么我的代码在关闭 channel 和所有工作人员退出后仍然存在死锁?

转载 作者:IT王子 更新时间:2023-10-29 02:31:09 24 4
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这是我的代码:

package main

import (
"fmt"
"sync"
)

func worker(id int, wg sync.WaitGroup, work <-chan int) {
defer func() {
wg.Done()
fmt.Println("worker", id, "done")
}()

fmt.Println("worker", id, "started")

for w := range work {
fmt.Println("worker", id, "got work", w)
}
}

func main() {

work := make(chan int, 2)
var wg sync.WaitGroup

for i := 0; i < 3; i++ {
wg.Add(1)
go worker(i, wg, work)
}

// Generate work and send.
for i := 0; i < 5; i++ {
work <- i
}

close(work)

fmt.Println("waiting ...")
wg.Wait()
fmt.Println("done")
}

这是输出:

worker 2 started
worker 2 got work 0
worker 2 got work 1
worker 2 got work 2
worker 1 started
waiting ...
worker 0 started
worker 0 done
worker 1 got work 4
worker 1 done
worker 2 got work 3
worker 2 done
fatal error: all goroutines are asleep - deadlock!

goroutine 1 [semacquire]:
sync.runtime_Semacquire(0xc42001409c)
/usr/local/Cellar/go/1.10.2/libexec/src/runtime/sema.go:56 +0x39
sync.(*WaitGroup).Wait(0xc420014090)
/usr/local/Cellar/go/1.10.2/libexec/src/sync/waitgroup.go:129 +0x72
main.main()
/Users/lone/bar/bar.go:39 +0x15f
exit status 2

为什么会出现这种死锁?

最佳答案

来自文档:

A WaitGroup must not be copied after first use.

尝试将指针传递给您的辅助函数:

func worker(id int, wg *sync.WaitGroup, work <-chan int)

完整代码如下:Playground

关于multithreading - 为什么我的代码在关闭 channel 和所有工作人员退出后仍然存在死锁?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53762085/

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