sorting - 这里是否生成了某种构造函数？

Question

在其中一个排序示例中，他们使用了以下代码:

package main

import (
    "fmt"
    "sort"
)

type Person struct {
    Name string
    Age  int
}

func (p Person) String() string {
    return fmt.Sprintf("%s: %d", p.Name, p.Age)
}

// ByAge implements sort.Interface for []Person based on
// the Age field.
type ByAge []Person

func (a ByAge) Len() int           { return len(a) }
func (a ByAge) Swap(i, j int)      { a[i], a[j] = a[j], a[i] }
func (a ByAge) Less(i, j int) bool { return a[i].Age < a[j].Age }

func main() {
    people := []Person{
        {"Bob", 31},
        {"John", 42},
        {"Michael", 17},
        {"Jenny", 26},
    }

    fmt.Println(people)
    sort.Sort(ByAge(people))
    fmt.Println(people)

}

排序的那一行让我有点困惑:

sort.Sort(ByAge(people))

ByAge(people) 是否生成某种构造函数来复制传入的数组？我不确定我是否理解新类型 ByAge 如何以其他方式访问元素。

Answer 1

foo(expr) 语法，其中 foo 是一个类型，expr 是一个类型转换，在 spec 中描述:

Conversions

Conversions are expressions of the form T(x) where T is a type and x is an expression that can be converted to type T.

Conversion = Type "(" Expression [ "," ] ")" .

If the type starts with the operator * or <-, or if the type starts with the keyword func and has no result list, it must be parenthesized when necessary to avoid ambiguity:

*Point(p)        // same as *(Point(p))
(*Point)(p)      // p is converted to *Point
<-chan int(c)    // same as <-(chan int(c))
(<-chan int)(c)  // c is converted to <-chan int
func()(x)        // function signature func() x
(func())(x)      // x is converted to func()
(func() int)(x)  // x is converted to func() int
func() int(x)    // x is converted to func() int (unambiguous)

A constant value x can be converted to type T in any of these cases:

• x is representable by a value of type T.
• x is a floating-point constant, T is a floating-point type, and x is representable by a value of type T after rounding using IEEE 754 round-to-even rules. The constant T(x) is the rounded value.
• x is an integer constant and T is a string type. The same rule as for non-constant x applies in this case.

Converting a constant yields a typed constant as result.

uint(iota)               // iota value of type uint
float32(2.718281828)     // 2.718281828 of type float32
complex128(1)            // 1.0 + 0.0i of type complex128
float32(0.49999999)      // 0.5 of type float32
string('x')              // "x" of type string
string(0x266c)           // "♬" of type string
MyString("foo" + "bar")  // "foobar" of type MyString
string([]byte{'a'})      // not a constant: []byte{'a'} is not a constant
(*int)(nil)              // not a constant: nil is not a constant, *int is not a boolean, numeric, or string type
int(1.2)                 // illegal: 1.2 cannot be represented as an int
string(65.0)             // illegal: 65.0 is not an integer constant

A non-constant value x can be converted to type T in any of these cases:

• x is assignable to T.
• x's type and Thave identical underlying types.
• x's type and T are unnamed pointer types and their pointer base types have identical underlying types.
• x's type and T are both integer or floating point types. x's type and T are both complex types.
• x is an integer or a slice of bytes or runes and T is a string type.
• x is a string and T is a slice of bytes or runes.

Specific rules apply to (non-constant) conversions between numeric types or to and from a string type. These conversions may change the representation of x and incur a run-time cost. All other conversions only change the type but not the representation of x.

There is no linguistic mechanism to convert between pointers and integers. The package unsafe implements this functionality under restricted circumstances.

有关详细信息，请参阅链接页面。