go - uint8, int8 的算术运算

Question

在给定示例的 unit8 和 int8 数据类型的算术运算中得到负数和零结果的原因是什么

package main

import (
    "fmt"
)

func main() {

     var u uint8 = 255
     fmt.Println(u, u+1, u*u) // "255 0 1"
     var i int8 = 127
     fmt.Println(i, i+1, i*i) // "127 -128 1"
}

https://play.golang.org/p/_a2KHP29t5p

Answer 1

Go 不会在运行时因整数溢出而 panic 。根据 doc :

For unsigned integer values, the operations +, -, *, and << are computed modulo 2n, where n is the bit width of the unsigned integer's type. Loosely speaking, these unsigned integer operations discard high bits upon overflow, and programs may rely on "wrap around".

For signed integers, the operations +, -, *, /, and << may legally overflow and the resulting value exists and is deterministically defined by the signed integer representation, the operation, and its operands. No exception is raised as a result of overflow. A compiler may not optimize code under the assumption that overflow does not occur. For instance, it may not assume that x < x + 1 is always true.