json - 在 Golang 中解析 Json

Question

一直在尝试使用 go 解析此 json 文件以获取最低和最高温度
给定城市的。

{
    "data": {
        "current_condition": [
            {
                "cloudcover": "25",
                "humidity": "56",
                "observation_time": "01:33 PM",
                "precipMM": "0.0",
                "pressure": "1016",
                "temp_C": "20",
                "temp_F": "68",
                "visibility": "10",
                "weatherCode": "116",
                "weatherDesc": [
                    {
                        "value": "Partly Cloudy"
                    }
                ],
                "weatherIconUrl": [
                    {
                        "value": "http://cdn.worldweatheronline.net/images/wsymbols01_png_64/wsymbol_0002_sunny_intervals.png"
                    }
                ],
                "winddir16Point": "SSW",
                "winddirDegree": "210",
                "windspeedKmph": "7",
                "windspeedMiles": "4"
            }
        ],
        "request": [
            {
                "query": "London, United Kingdom",
                "type": "City"
            }
        ],
        "weather": [
            {
                "date": "2014-09-07",
                "precipMM": "0.0",
                "tempMaxC": "23",
                "tempMaxF": "74",
                "tempMinC": "10",
                "tempMinF": "49",
                "weatherCode": "119",
                "weatherDesc": [
                    {
                        "value": "Cloudy"
                    }
                ],
                "weatherIconUrl": [
                    {
                        "value": "http://cdn.worldweatheronline.net/images/wsymbols01_png_64/wsymbol_0003_white_cloud.png"
                    }
                ],
                "winddir16Point": "N",
                "winddirDegree": "355",
                "winddirection": "N",
                "windspeedKmph": "9",
                "windspeedMiles": "6"
            }
        ]
    }
}  

已成功使用结构和解码 json 字符串。
现在我想尝试使用 map ，例如 map[string]interface{}

如果u是map[string]interface{}类型，json解析成u，
u["data"].(map[string]interface{})["weather"]
给出值

http://api.worldweatheronline.com/free/v1/weather.ashx?q=london&format=json&num_of_days=1&key=8c52bb73c5f6160f5f3aa535d22184638372d22b [map[tempMaxC:23 tempMaxF:74 tempMinC:10 tempMinF:49 winddirection:N windspeedMiles:6 date:2014-09-07 precipMM:0.0 weatherCode:119 winddir16Point:N winddirDegree:355 weatherDesc:[map[value:Cloudy]] weatherIconUrl:[map[value:http://cdn.worldweatheronline.net/images/wsymbols01_png_64/wsymbol_0003_white_cloud.png]] windspeedKmph:9]]

而 u["data"].(map[string]interface{})["weather"].(map[string]interface{})["tempMinC"],
给我一个 panic: interface conversion: interface is []interface {}, not map[string]interface {}

谁能解释一下发生了什么？

Answer 1

u["data"].(map[string]interface{})["weather"] 是 map 的一部分，而不是 map ，因此您必须执行以下操作:

maps, ok := u["data"].(map[string]interface{})["weather"].([]interface{})
if !ok {
     panic("bad json")
}
for _, m := range maps {
     if m, ok := m.(map[string]interface{}); ok {
          fmt.Println(m["tempMinC"])
     }
}

在您的 JSON 示例中，weather 是一个对象数组，因此在 Go 中这会转换为一片 map ([]map[string]interface{})。