xml - 将嵌套的 xml 解码为结构

Question

如何在 Go 中为嵌套的 xml 内容创建结构？想象一下这个 xml:

<?xml version="1.0" encoding="UTF-8"?>
<people>
  <person>
    <name>Pers1</name>
    <gender>female</gender>
    <somethings>
      <thing>123</thing>
      <thing>321</thing>
    </somethings>
  </person>
  <person>
    <name>Pers2</name>
    <gender>male</gender>
    <somethings>
      <thing>111</thing>
      <thing>222</thing>
      <thing>333</thing>
    </somethings>
  </person>
  <person>
    <name>Pers3</name>
    <gender>female</gender>
    <somethings>
      <thing>978</thing>
    </somethings>
  </person>
  <!-- And so on... -->
</people>

我能够加载数据，但无法为这种嵌套数据创建结构。你知道的每一个技巧都会很高兴!

祝你有个美好的一天! :)

Answer 1

type Data struct {
    People []Person `xml:"person"`
}

type Person struct {
    Name       string   `xml:"name"`
    Gender     string   `xml:"gender"`
    Somethings []string `xml:"somethings>thing"`
}

https://play.golang.org/p/q2CKAfiiwQ