xml - Golang : get inner xml from xml with xml.解码

Question

我有这样简单的 XML:

<?xml version="1.0" encoding="ISO-8859-1"?>
  <nexgen_audio_export>
    <audio ID="id_1667331726_30393658">
      <type>Song</type>
      <status>Playing</status>
      <played_time>09:41:18</played_time>
      <composer>Frederic Delius</composer>
      <title>Violin Sonata No.1</title>
      <artist>Tasmin Little, violin; Piers Lane, piano</artist>
      <comments>
         <p>Comment line1</p>
         <p>Comment <b>line2</b></p>
         <p>Comment line3</p>
      </comments>
    </audio>
  </nexgen_audio_export>

如何从 xml:"nexgen_audio_export>audio>comments" 获取内部 XML所有标签( <p> 、 <b> 等)都使用 xml.decode？

谢谢，美联社

Answer 1

来自 https://golang.org/pkg/encoding/xml/#Unmarshal :

If the struct has a field of type []byte or string with tag ",innerxml", Unmarshal accumulates the raw XML nested inside the element in that field.

您可以只将结构标记 ",innerxml" 用于您元素内部的 string 或 []byte 类型的字段'试图从中提取 XML。您需要使用子结构。另请注意，XML 库的选择查询从第一个元素开始(这很奇怪)。因此，您不能以 nexgen_audio_export> 开始标记，而是直接转到 audio>。

这是工作示例代码:

package main

import (
    "encoding/xml"
    "fmt"
)

// Encoding had to be changed to UTF-8
var input = []byte(`<?xml version="1.0" encoding="UTF-8"?>
  <nexgen_audio_export>
    <audio ID="id_1667331726_30393658">
      <type>Song</type>
      <status>Playing</status>
      <played_time>09:41:18</played_time>
      <composer>Frederic Delius</composer>
      <title>Violin Sonata No.1</title>
      <artist>Tasmin Little, violin; Piers Lane, piano</artist>
      <comments>
         <p>Comment line1</p>
         <p>Comment <b>line2</b></p>
         <p>Comment line3</p>
      </comments>
    </audio>
  </nexgen_audio_export>`)

type audio struct {
    Comments struct {
        InnerXML string `xml:",innerxml"`
    } `xml:"audio>comments"`
}

func main() {
    var a audio
    err := xml.Unmarshal(input, &a)
    if err != nil {
        panic(err)
    }

    fmt.Println(a.Comments.InnerXML)
}

Playground 链接:https://play.golang.org/p/LAL2V0zExc