go - time.Millisecond * int 混淆

Question

在下面的示例中，如果 1000 都是整数(我认为它们是)，为什么底部无法编译？

//works
time.Sleep(1000 * time.Millisecond)

//fails
var i = 1000
time.Sleep(i * time.Millisecond)

Answer 1

Operators

Operators combine operands into expressions.

Comparisons are discussed elsewhere. For other binary operators, the operand types must be identical unless the operation involves shifts or untyped constants. For operations involving constants only, see the section on constant expressions.

Except for shift operations, if one operand is an untyped constant and the other operand is not, the constant is converted to the type of the other operand.

例如，使用“*”(乘法)运算符，

package main

import (
    "time"
)

func main() {

    // works - 1000 is an untyped constant
    // which is converted to type time.Duration
    time.Sleep(1000 * time.Millisecond)

    // fails - v is a variable of type int
    // which is not identical to type time.Duration
    var v = 1000
    // invalid operation: i * time.Millisecond (mismatched types int and time.Duration)
    time.Sleep(v * time.Millisecond)
}