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Go:深拷贝 slice

转载 作者:IT王子 更新时间:2023-10-29 01:43:14 26 4
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我想读取一段表示十六进制数的字符串,并将它们解码为一段 byte slice 段 ([]string --> [][]byte)。到目前为止,这是我的代码:

func (self *algo_t) decode_args(args []string) ([][]byte, error) {
var data [][]byte
for i := uint32(0); i < self.num_args; i++ {
data = make([][]byte, self.num_args)
tmp, err := hex.DecodeString(args[i])
fmt.Printf("i = %d\ttmp = %x\n", i, tmp)
data[i] = make([]byte, len(tmp))
copy(data[i], tmp)
if err != nil {
fmt.Fprintf(os.Stderr, "Error decoding hex string %s: %s\n", args[i], err.Error())
return nil, err
}
}
fmt.Printf("line 69\tdata[0] = %x\tdata[1] = %x\tdata[2] = %x\n",data[0], data[1], data[2])
return data, nil
}

调用此代码并传递 args = []string{"010203","040506","070809"} 会产生以下输出:

i = 0    tmp = 010203
i = 1 tmp = 040506
i = 3 tmp = 070809
line 69 data[0] = data[1] = data[2] = 070809

推测该函数返回 [][]byte{[]byte{}, []byte{}, []byte{0x07, 0x08, 0x09}}

我理解这是因为 Go 的指针行为;执行此类深拷贝的最佳做法是什么?

最佳答案

例如,

package main

import (
"encoding/hex"
"fmt"
)

// Decode hex []string to [][]byte
func decode(s []string) ([][]byte, error) {
b := make([][]byte, len(s))
for i, ss := range s {
h, err := hex.DecodeString(ss)
if err != nil {
err = fmt.Errorf(
"Error decoding hex string %s: %s\n",
ss, err.Error(),
)
return nil, err
}
b[i] = h
}
return b, nil
}

func main() {
s := []string{"010203", "040506", "070809"}
fmt.Println(s)
b, err := decode(s)
if err != nil {
fmt.Println(err)
} else {
fmt.Println(b)
}
s = []string{"ABCDEF", "012345", "09AF"}
fmt.Println(s)
b, err = decode(s)
if err != nil {
fmt.Println(err)
} else {
fmt.Println(b)
}
s = []string{"01", "123XYZ"}
fmt.Println(s)
b, err = decode(s)
if err != nil {
fmt.Println(err)
} else {
fmt.Println(b)
}
}

输出:

[010203 040506 070809]
[[1 2 3] [4 5 6] [7 8 9]]
[ABCDEF 012345 09AF]
[[171 205 239] [1 35 69] [9 175]]
[01 123XYZ]
Error decoding hex string 123XYZ: encoding/hex: invalid byte: U+0058 'X'

关于Go:深拷贝 slice ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23255629/

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