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go - 使用 Go 从 PEM 格式的 Google "oauth2/v1/certs"证书中提取公钥

转载 作者:IT王子 更新时间:2023-10-29 01:43:05 25 4
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我从以下位置获取了 Google 证书:

https://www.googleapis.com/oauth2/v1/certs

但我不知道如何在 Go 中解析证书并提取公钥并使其适用于 rsa.VerifyPKCS1v15() 以验证 ID token (openID 连接)签名。如果有人可以建议我,我将不胜感激。这是我已有的代码:

res, err := http.Get("https://www.googleapis.com/oauth2/v1/certs")
if err != nil {
log.Fatal(err)
return
}

certs, err := ioutil.ReadAll(res.Body)
res.Body.Close()
if err != nil {
log.Fatal(err)
return
}
//extract kid from token header
var header interface{}
log.Printf("Oauth header: %v", headerOauth)
err = json.Unmarshal([]byte(headerOauth), &header)

token_kid := header.(map[string]interface{})["kid"]
//get modulus and exponent from the cert

var goCertificate interface{}

err = json.Unmarshal(certs, &goCertificate)

k := goCertificate.(map[string]interface{})[token_kid.(string)]

google_cert := k.(string)
block_pub, _ := pem.Decode([]byte(google_cert))
certInterface, err := x509.ParseCertificates(block_pub.Bytes)
log.Printf("certInterface: %v", *certInterface.PublicKey)
//I know the line below is wrong but thats how I usualy parse public keys
pubkeyInterface, err := x509.ParsePKIXPublicKey(certInterface.Bytes)
pKey, ok := pubkeyInterface.(*rsa.PublicKey)

最佳答案

我可能跑题了(不熟悉 x509/rsa)但是 ParseCertificates 返回了所有的键:

func main() {
res, err := http.Get("https://www.googleapis.com/oauth2/v1/certs")
if err != nil {
log.Fatal(err)
return
}

var header = map[string]string{
"kid": "ef9007a67db85f13ed67462abe2df63145c09aaf",
}

token_kid := header["kid"]

defer res.Body.Close()
var certs map[string]string
dec := json.NewDecoder(res.Body)
dec.Decode(&certs)
// add error checking
google_cert := certs[token_kid]
block_pub, _ := pem.Decode([]byte(google_cert))
certInterface, err := x509.ParseCertificates(block_pub.Bytes)
log.Printf("certInterface: %#v", certInterface)
pkey := certInterface[0].PublicKey.(*rsa.PublicKey)
log.Printf("pkey: %v", pkey)
}

关于go - 使用 Go 从 PEM 格式的 Google "oauth2/v1/certs"证书中提取公钥,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26237283/

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