go - 测试多次调用构造函数的地方？

Question

import (
    "testing"
    "github.com/stretchr/testify/assert"
)

func TestNewPerson(t *testing.T) {
    firstName := "Barack"
    lastName := "Obama"
    birthYear := 1990

    p, err := NewPerson(firstName, lastName, birthYear)

    assert.Equal(t, err, nil, "Should not return error.")
    assert.Equal(t, p.FirstName, firstName, "First name came wrong.")
    assert.Equal(t, p.LastName, lastName, "Last name came wrong.")
    assert.Equal(t, p.BirthYear, birthYear, "Birth year name came wrong.")
}

func TestFullName(t *testing.T) {
    tests := []struct{
        firstName   string
        lastName    string
        fullName    string
    }{
        {"Hello", "World", "Hello World",},
        {"Barack", "Hussein Obama ", "Barack Hussein Obama",},
    }

    for _, obj := range tests {
        p, _  := NewPerson(obj.firstName, obj.lastName, 1990)

        assert.Equal(t, obj.fullName, p.FullName())
    }
}

这很好用。但是当我编写了很多测试，然后我需要在“NewPerson”构造函数中进行更改时会发生什么，因为我向结构添加了一个新属性？

然后我将不得不更改对构造函数的调用的所有参数。

有什么解决方案？我应该寻找一种方法来抽象它吗？

Answer 1

那种重构可以(未测试)用 command go fmt 来处理.

参见“Refactoring with go fmt”:

gofmt uses patterns to identify changes to make to your code. Patterns are established in the first half the expression followed by a ‘->’ then used by the second half of the expression.

Use the flag -d instead of -w to check what gofmt will do prior to running it.

gofmt -r "yourConstructor(x,y) -> yourConstructor(x, y, z)" -d ./

仅当您指定的模式是有效的 go expression 时才有效，如 this answer 中所述.