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json - 如何格式化具有多个对象返回的 json 结构? (动态的)

转载 作者:IT王子 更新时间:2023-10-29 01:39:29 25 4
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我有一个 API 调用,它返回如下:

{
"result": {
"720268538": {
"icon_url": "-9a81dlWLwJ2UUGcVs_nsVtzdOEdtWwKGZZLQHTxDZ7I56KU0Zwwo4NUX4oFJZEHLbXU5A1PIYQNqhpOSV-fRPasw8rsUFJ5KBFZv668FFEuh_KQJTtEuI63xIXbxqOtauyClTMEsJV1jruS89T3iQKx_BBqa2j3JpjVLFH1xpp0EQ",
"icon_url_large": "",
"icon_drag_url": "",
"name": "Chroma Case",
"market_hash_name": "Chroma Case",
"market_name": "Chroma Case",
"name_color": "D2D2D2",
"background_color": "",
"type": "Base Grade Container",
"tradable": "1",
"marketable": "1",
"commodity": "1",
"market_tradable_restriction": "7",
"fraudwarnings": "",
"descriptions": {
"0": {
"type": "html",
"value": " ",
"app_data": ""
},
"1": {
"type": "html",
"value": "Container Series #38",
"color": "99ccff",
"app_data": ""
},
"2": {
"type": "html",
"value": " ",
"app_data": ""
},
"3": {
"type": "html",
"value": "Contains one of the following:",
"app_data": ""
},
"4": {
"type": "html",
"value": "Glock-18 | Catacombs",
"color": "4b69ff",
"app_data": ""
},
"5": {
"type": "html",
"value": "M249 | System Lock",
"color": "4b69ff",
"app_data": ""
},
"6": {
"type": "html",
"value": "MP9 | Deadly Poison",
"color": "4b69ff",
"app_data": ""
},
"7": {
"type": "html",
"value": "SCAR-20 | Grotto",
"color": "4b69ff",
"app_data": ""
},
"8": {
"type": "html",
"value": "XM1014 | Quicksilver",
"color": "4b69ff",
"app_data": ""
},
"9": {
"type": "html",
"value": "Dual Berettas | Urban Shock",
"color": "8847ff",
"app_data": ""
},
"10": {
"type": "html",
"value": "Desert Eagle | Naga",
"color": "8847ff",
"app_data": ""
},
"11": {
"type": "html",
"value": "MAC-10 | Malachite",
"color": "8847ff",
"app_data": ""
},
"12": {
"type": "html",
"value": "Sawed-Off | Serenity",
"color": "8847ff",
"app_data": ""
},
"13": {
"type": "html",
"value": "AK-47 | Cartel",
"color": "d32ce6",
"app_data": ""
},
"14": {
"type": "html",
"value": "M4A4 | 龍王 (Dragon King)",
"color": "d32ce6",
"app_data": ""
},
"15": {
"type": "html",
"value": "P250 | Muertos",
"color": "d32ce6",
"app_data": ""
},
"16": {
"type": "html",
"value": "AWP | Man-o'-war",
"color": "eb4b4b",
"app_data": ""
},
"17": {
"type": "html",
"value": "Galil AR | Chatterbox",
"color": "eb4b4b",
"app_data": ""
},
"18": {
"type": "html",
"value": "or an Exceedingly Rare Special Item!",
"color": "ffd700",
"app_data": ""
},
"19": {
"type": "html",
"value": " ",
"app_data": ""
},
"20": {
"type": "html",
"value": "",
"color": "00a000",
"app_data": {
"limited": "1"
}
}
},
"owner_descriptions": "",
"tags": {
"0": {
"internal_name": "CSGO_Type_WeaponCase",
"name": "Container",
"category": "Type",
"category_name": "Type"
},
"1": {
"internal_name": "set_community_6",
"name": "The Chroma Collection",
"category": "ItemSet",
"category_name": "Collection"
},
"2": {
"internal_name": "normal",
"name": "Normal",
"category": "Quality",
"category_name": "Category"
},
"3": {
"internal_name": "Rarity_Common",
"name": "Base Grade",
"category": "Rarity",
"color": "b0c3d9",
"category_name": "Quality"
}
},
"classid": "720268538"
},
"success": true
}
}

结果可以有多个返回我想知道结构应该是什么样子,这就是我到目前为止所拥有的,但它什么也没有返回。

type AssetInfo struct {
Result `json:"result"`
}

type Result struct {
Asset map[string]Asset `json:"asset"`
Success bool `json:"success,omitempty"`
}

type Asset struct {
IconUrl string `json:"icon_url,omitempty"`
IconUrlLarge string `json:"icon_url_large,omitempty"`
IconDragUrl string `json:"icon_drag_url,omitempty"`
Name string `json:"name,omitempty"`
MarketHashName string `json:"market_hash_name,omitempty"`
MarketName string `json:"market_name,omitempty"`
NameColor string `json:"name_color,omitempty"`
BGColor string `json:"background_color,omitempty"`
Type string `json:"type,omitempty"`
Tradable string `json:"tradable,omitempty"`
Marketable string `json:"marketable,omitempty"`
Commodity string `json:"commodity,omitempty"`
TradeRestrict string `json:"market_tradeable_restriction,omitempty"`
FraudWarnings string `json:"fraudwarnings,omitempty"`
Descriptions map[string]*Descriptions `json:"descriptions,omitempty"`
OwnerDescriptions string `json:"owner_descriptions,omitempty"`
Tags map[string]*Tags `json:"tags,omitempty"`
ClassId string `json:"classid,omitempty"`
}

type Descriptions struct {
Type string `json:"type"`
Value string `json:"value"`
Color string `json:"color,omitempty"`
AppData string `json:"appdata"`
}

type Tags struct {
InternalName string `json:"internal_name"`
Name string `json:"name"`
Category string `json:"category"`
Color string `json:"color,omitempty"`
CategoryName string `json:"category_name"`
}

如果有人能告诉我我的结构有什么问题,那将非常感谢。

让我感到困惑的是,Descriptions 如何返回的不是一个数组,而是多个范围从 0 到 20 的对象,当我不知道要返回多少对象时,我该如何为此准备一个结构? result 可以返回多个 "720616831" 那么这看起来应该如何?

最佳答案

你会因为第一个错误而自责——你的 JSON 有 result 但你的 struct 标签有 response

第二个问题比较棘手。问题是您声明您的 Asset map 作为名为“asset”的键嵌套在结果中,但事实并非如此。实际上它只是结果的所有键 other 而不是成功/错误。不幸的是,encoding/json 没有任何方式来表达这一点。你可以说 result 是一个 map[string]interface{},然后 success/error 如果它们存在将是 bool/string, Assets 将更多 map[string]interface{} 包含所有其他字段的键。这行得通,但它有点难看/效率低下,如果您想转换为适当的结构类型以便可以在其上拥有方法,则需要做很多工作。

也许更好的方法是解码成这种类型:

type AssetIntermediate struct {
Result map[string]json.RawMessage `json:"result"`
}

还有

type Asset struct { /* all those fields */ }
type AssetInfo struct {
Success bool
Error string
Assets map[string]Asset
}

然后你可以做

var intermediate AssetIntermediate
err := json.Unmarshal(data, &intermediate)
/* handle err */

var ai AssetInfo

/* At this point, intermediate.Result is a map
* of strings to json.RawMessage, which is just a []byte
* containing not-yet-decoded JSON. We want to take
* each field and put it into ai where it belongs.
*/
for k, v := range intermediate.Result {
var err error
// error and success keys are decoded into the respective fields
if k == "error" {
err = json.Unmarshal(v, &ai.Error)
} else if k == "success" {
err = json.Unmarshal(v, &ai.Success)
} else {
// Otherwise, we have an asset. First decode it...
var asset Asset
err = json.Unmarshal(v, &asset)
if err == nil {
// Create the Assets map if it doesn't exist yet
if ai.Assets == nil {
ai.Assets = map[string]Asset{}
}
// And store the asset in the map under the key k.
ai.Assets[k] = asset
}
}
/* handle err if non-nil */
}

这比单个 Decode 调用要多得多,但它基本上应该做正确的事情。

如果所有这些都在返回 (*AssetInfo, error) 的函数中,那么替换 /* Handle err */ 的正确方法可能是

if err != nil {
return nil, err
}

关于json - 如何格式化具有多个对象返回的 json 结构? (动态的),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32281711/

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