go - 将 Struct 传递给 redigo Send 函数会破坏它并且数据丢失

Question

这是我的结构，当我收到套接字消息时，我读取了 Json 并且结构中填充了数据，一切都很好。它通过一些函数，但是一旦它通过发送函数，它就会以一种奇怪的方式对其进行序列化，最终我得到一堆数字，当我将它转换为字符串时，数据丢失了。

type Reply struct {
  Topic   string `redis:"topic" json:"topic"`
  Ref string `redis:"ref" json:"ref"`
  Payload struct {
      Status string `redis:"status" json:"status"`
      Response map[string]interface{} `redis:"response" json:"response"`
  } `json:"payload"`
}

我只想以这种格式广播消息。

这是我得到修改过的和有问题的数据的地方

func (rr *redisReceiver) run() error {
  l := log.WithField("channel", Channel)
  conn := rr.pool.Get()
  defer conn.Close()
  psc := redis.PubSubConn{Conn: conn}
  psc.Subscribe(Channel)
  go rr.connHandler()
  for {
    switch v := psc.Receive().(type) {
    case redis.Message:
        rr.broadcast(v.Data)
    case redis.Subscription:
        l.WithFields(logrus.Fields{
            "kind":  v.Kind,
            "count": v.Count,
        }).Println("Redis Subscription Received")
        log.Println("Redis Subscription Received")
    case error:
        return errors.New("Error while subscribed to Redis channel")
    default:
        l.WithField("v", v).Info("Unknown Redis receive during subscription")
        log.Println("Unknown Redis receive during subscription")
    }
  }
}

难道Redigo不支持那种数据结构吗？

这是我得到的格式和我应该得​​到的格式。

//Get
"{{spr_reply sketchpad map[] 1} {ok map[success:Joined successfully]}}"
//Supposed to get
{event: "spr_reply", topic: "sketchpad", ref: "45", payload: {status: 
"ok", response: {}}}

第 55 行是我取回“损坏”数据的地方 - https://play.golang.org/p/TOzJuvewlP

Answer 1

雷戈 supports the following conversions to Redis bulk strings :

Go Type                 Conversion
[]byte                  Sent as is
string                  Sent as is
int, int64              strconv.FormatInt(v)
float64                 strconv.FormatFloat(v, 'g', -1, 64)
bool                    true -> "1", false -> "0"
nil                     ""
all other types         fmt.Print(v)

Reply 类型使用 fmt.Print(v) 进行编码。

您似乎想将值编码为 JSON。如果是这样，请在应用程序中进行编码。您可以删除 redis 字段标签。

writeToRedis(conn redis.Conn, data Reply) error {
    p, err := json.Marshl(data)
    if err != nil {
        return errors.Wrap(err, "Unable to encode message to json")
    }
    if err := conn.Send("PUBLISH", Channel, p); err != nil {
        return errors.Wrap(err, "Unable to publish message to Redis")
    }
    if err := conn.Flush(); err != nil {
        return errors.Wrap(err, "Unable to flush published message to Redis")
    }
    return nil
}