xml - GOLang XML 无法使用 xml.MarshalIndent 在一个标记中创建值和属性

Question

Go 的新手，必须使用“encoding/xml”包中的 xml.MarshalIndent 创建 xml 文件。一个要求是像这样创建一个标签:

`

   <Attributes>
      <Attribute name="Me">I really like this GO lang</Attribute>
      <Attribute name="problem">the xml package is not behaving</Attribute>
   </Attributes>

`

一组带有值和属性的标签，但无论我做什么(我尝试了很多不同的方法)，我就是无法让它工作。

我编写的代码生成了这个:`

<Attributes>
    <Attribute Name="J3K Solutions">
        <Attribute>IT Support</Attribute>
    </Attribute>
    <Attribute Name="stakoverflow">
        <Attribute>The place I go for help</Attribute>
    </Attribute>
</Attributes>

`

但是我需要它看起来像这样:`

<Attributes>
    <Attribute Name="J3K Solutions" >IT Support</Attribute>
    <Attribute Name="stakoverflow" >The place I go for help</Attribute>
</Attributes>

`我一直在阅读文档，并试图让它工作几个小时。有人知道这是否可行吗？

代码:

 package main

import (
    "encoding/xml"
    "fmt"
    "time"
)

type attributes struct {
    Name      string `xml:",attr"`
    Attribute string `xml:"Attribute"`
}

type fXML struct {
    MessageID string `xml:"MessageID,attr"`
    Timestamp string `xml:"timestamp,attr"`
    Version   string `xml:"version,attr"`
    Header    struct {
        From struct {
            Credential struct {
                Domain   string `xml:"domain,attr"`
                Identity string `xml:"Identity"`
            } `xml:"Credential"`
        } `xml:"From"`
        To struct {
            Credential struct {
                Domain   string `xml:"domain,attr"`
                Identity string `xml:"Identity"`
            } `xml:"Credential"`
        } `xml:"To"`
        Attributes struct {
            Attribute []attributes
        }
    } `xml:"Header"`
}

func main() {

rdata := &fXML{}
t := time.Now()
rdata.MessageID = "I'm really liken this GO language!"
rdata.Timestamp = t.Format("2006-01-02T15:04:05")
rdata.Version = "1.0"
rdata.Header.From.Credential.Domain = "j3ksolutions.com"
rdata.Header.From.Credential.Identity = "J3K Solutions"
rdata.Header.To.Credential.Domain = "stackoverflow.com"
rdata.Header.To.Credential.Identity = "stackoverflow"
rdata.Header.Attributes.Attribute = append(rdata.Header.Attributes.Attribute,
    attributes{
        Name:      "J3K Solutions",
        Attribute: "IT Support and Custom Programing",
    })
rdata.Header.Attributes.Attribute = append(rdata.Header.Attributes.Attribute,
    attributes{
        Name:      "stakoverflow",
        Attribute: "The place I go for help",
    })

if m, err2 := xml.MarshalIndent(rdata, "", "\t"); err2 != nil {
    panic("xml.MarshalIndent FAILED: " + err2.Error())
} else {
    xmlheader := fmt.Sprintf("<?xml version=\"1.0\" encoding=\"ISO-8859-1\" ?>\n")
    m = append([]byte(xmlheader), m...)
    fmt.Printf("\n%s\n\n", m)
}
}

Answer 1

您可能需要使用“,chardata”结构标签来写入字符数据。这是doc说

• a field with tag ",chardata" is written as character data, not as an XML element.

您可以按如下方式定义结构

type attributes struct {
    XMLName   xml.Name `xml:Attribute"`
    Name      string   `xml:",attr"`
    Attribute string   `xml:",chardata"`
}

这是播放链接:go play