Golang Gin-Gonic 将路由拆分成多个文件

Question

我希望将我的 routes.go 分成多个文件，以便每个组都在自己的包中。有人可以指出一些代码示例，其中有人使用 Gin 完成了此操作吗？

即

package auth
...
auth = route.Group("/auth"){
    auth.GET(...
    auth.POST(...
}
...

package users
...
user = route.Group("/user"){
    user.GET(...
    user.POST(...
}
...

package main
import (
     "auth"
     "users"
)
...
router = gin.Default()
router.Register(auth.auth, users.user)
router.Run()
...

Answer 1

这样做的方法是在每个函数中创建一个函数，将路由作为参数，然后将路由添加到参数中:

package auth
import "...gin"
func Routes(route *gin.Engine)
auth := route.Group("/auth"){
    auth.GET(...
    auth.POST(...
}
...

package users
import "...gin"
func Routes(route *gin.Engine)
user := route.Group("/user"){
    user.GET(...
    user.POST(...
}
...

package main
import (
     "github.com/username/package/sub/auth"
     "github.com/username/package/sub/users"
     "github.com/gin-gonic/gin"
)
...
router := gin.Default()
auth.Routes(router) //Added all auth routes
user.Routes(router) //Added all user routes
router.Run()
...