json - 如何在 Go1.9 中将 json 字符串解码为 sync.Map 而不是法线贴图？

Question

我可以像这样使用 go 语言将 json 字符串解码为映射:

func main(){
  date := []byte(`{"127.1":{"host":"host1","list":["list123","list456"]},"127.2":{"host":"host2","list":["list223","list256"]}}`)
  var x interface{}
  json.Unmarshal(date, &x)
  t := x.(map[string]interface{})
  var aa []interface{}
  aa = (t["127.2"].(map[string]interface{})["list"])
  for _, v := range aa {
     fmt.Println(v.(string))
  }
}

但我想知道如何在 Go1.9 中将它解码为 sync.Map。我试了很多方法都失败了，谁能帮帮我？

我试过这样的:

    func main(){
      date := []byte(`{"127.1":{"host":"host1","list":["list123","list456"]},"127.2":{"host":"host2","list":["list223","list256"]}}`)
      var x interface{}
      json.Unmarshal(date, &x)
      t := x.((sync.Map)[string]interface{})  //compile error
}

我也这样试过:

    func main(){
      date := []byte(`{"127.1":{"host":"host1","list":["list123","list456"]},"127.2":{"host":"host2","list":["list223","list256"]}}`)
      var x sync.Map
      json.Unmarshal(date, &x)
      fmt.Println(x) // but the map has nothing
}

Answer 1

如果你需要一个片段来做另一种方式

func (f Foo) MarshalJSON() ([]byte, error) {
    tmpMap := make(map[YourTypeOfKey]YourTypeOfValue)
    f.Range(func(k, v interface{}) bool {
        tmpMap[k.(YourTypeOfKey)] = v.(YourTypeOfValue)
        return true
    })
    return json.Marshal(tmpMap)
}