c - 带分隔符的Strtok行为

Question

下面是代码片段。

#define TABLE_DELIMITER "::"
int parse_n_store ( char *line )
{

        int i = 0;
        char *p = NULL;
        CPTR sensor_number = NULL , event_catagory = NULL, sensor_type = NULL, event_state= NULL, assertion = NULL, message_number = NULL, short_text = NULL;

        for (p = strtok(line,TABLE_DELIMITER); p != NULL; p = strtok(NULL, TABLE_DELIMITER), i++ )
        {
                if ( i == 0 )
                        sensor_number=p;
                else if ( i == 1 )
                        sensor_type = p;
                else if ( i == 2 )
                        event_catagory = p;
                else if ( i == 3 )
                        event_state = p;
                else if ( i == 4 )
                        assertion = p;
                else if ( i == 5 )
                        message_number = p;
                else if ( i == 6 )
                        short_text = p;
        }

        printf ("%s %s %s %s %s %s %s\n", sensor_number, event_catagory, sensor_type, event_state, assertion, message_number, short_text);
}

这很好用。但是，当“行”参数是“前板内存状态:检测到可纠正的 ECC/其他可纠正的内存错误时；传感器(70，内存)”

输出将是

70 SENSOR_SPECIFIC MEMORY STATE_00 True 8543 前板内存状态

其中 short_text 变量仅包含“前板内存状态”而不是“前板内存状态:检测到可纠正的 ECC/其他可纠正的内存错误；传感器(70，内存)”

为什么 strtok 将单个冒号视为分隔符？谁能解决这个问题。

Answer 1

Why strtok considering a single colon as delimiter?

因为在标准(C11)中有规定:

7.24.5.8 The strtok function

[...]

2. A sequence of calls to the strtok function breaks the string pointed to by s1 into asequence of tokens, each of which is delimited by a character from the string pointed toby s2. The first call in the sequence has a non-null first argument; subsequent calls in thesequence have a null first argument. The separator string pointed to by s2 may bedifferent from call to call.