linux - 获取引号之间的单词

Question

我有 x 行是这样的:

Unable to find latest released revision of 'CONTRIB_046578'.   

我需要提取 ' 和 ' 之间的单词，在此示例中，单词 CONTRIB_046578，如果可能的话，计算数量使用 grep、sed 或任何其他命令出现该词的次数？

Answer 1

最干净的解决方案是 grep -Po "(?<=')[^']+(?=')"

$ cat file
Unable to find latest released revision of 'CONTRIB_046578'
Unable to find latest released revision of 'foo'
Unable to find latest released revision of 'bar'
Unable to find latest released revision of 'CONTRIB_046578'

# Print occurences 
$ grep -Po "(?<=')[^']+(?=')" file
CONTRIB_046578
foo
bar
CONTRIB_046578

# Count occurences
$ grep -Pc "(?<=')[^']+(?=')" file
4

# Count unique occurrences 
$ grep -Po "(?<=')[^']+(?=')" file | sort | uniq -c 
2 CONTRIB_046578
1 bar
1 foo