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我有一个带有传入消息的 channel 和一个等待它的例程我处理这些消息并将它们发送到不同的服务器
如果准备好,我想一次处理 100 条消息,或者在说 5 秒后处理那里的内容,然后再等待
我如何在 Go 中做到这一点
最佳答案
用于从消息 channel 读取的例程应该定义一个缓存,其中存储传入的消息。然后,当缓存达到 100 条消息或 5 秒后,这些缓存的消息将批量发送到远程服务器。您使用计时器 channel 和 Go 的 select
语句来确定哪个先发生。
以下示例可以在 Go playground 上运行
package main
import (
"fmt"
"math/rand"
"time"
)
type Message int
const (
CacheLimit = 100
CacheTimeout = 5 * time.Second
)
func main() {
input := make(chan Message, CacheLimit)
go poll(input)
generate(input)
}
// poll checks for incoming messages and caches them internally
// until either a maximum amount is reached, or a timeout occurs.
func poll(input <-chan Message) {
cache := make([]Message, 0, CacheLimit)
tick := time.NewTicker(CacheTimeout)
for {
select {
// Check if a new messages is available.
// If so, store it and check if the cache
// has exceeded its size limit.
case m := <-input:
cache = append(cache, m)
if len(cache) < CacheLimit {
break
}
// Reset the timeout ticker.
// Otherwise we will get too many sends.
tick.Stop()
// Send the cached messages and reset the cache.
send(cache)
cache = cache[:0]
// Recreate the ticker, so the timeout trigger
// remains consistent.
tick = time.NewTicker(CacheTimeout)
// If the timeout is reached, send the
// current message cache, regardless of
// its size.
case <-tick.C:
send(cache)
cache = cache[:0]
}
}
}
// send sends cached messages to a remote server.
func send(cache []Message) {
if len(cache) == 0 {
return // Nothing to do here.
}
fmt.Printf("%d message(s) pending\n", len(cache))
}
// generate creates some random messages and pushes them into the given channel.
//
// Not part of the solution. This just simulates whatever you use to create
// the messages by creating a new message at random time intervals.
func generate(input chan<- Message) {
for {
select {
case <-time.After(time.Duration(rand.Intn(100)) * time.Millisecond):
input <- Message(rand.Int())
}
}
}
关于Go,我如何一次从一个 channel 中提取 X 条消息,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20855472/
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