linux - 查找不在列表中的文件

Question

我在 file.lst 中有一个文件列表。现在我想在目录 dir 中找到所有超过 7 天的文件，file.lst 文件中的文件除外。如何修改查找命令或从结果中删除 file.lst 中的所有条目？

例子:

文件.lst:

a
b
c

执行:

find -mtime +7 -print > found.lst

found.lst:

a
d
e

所以我期望的是:

d
e

Answer 1

通过 grep -Fxvf 管道化您的 find 命令:

find -mtime +7 -print | grep -Fxvf file.lst

标志的含义:

-F, --fixed-strings
              Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched.    
-x, --line-regexp
              Select only those matches that exactly match the whole line.
-v, --invert-match
              Invert the sense of matching, to select non-matching lines.
-f FILE, --file=FILE
              Obtain patterns from FILE, one per line.  The empty file contains zero patterns, and therefore matches nothing.