php - 使用当前时间和以天为键、以连字符分隔的时间范围为值的数组检查企业是否营业

Question

我正在尝试计算当前时间是否在餐厅的营业时间内。

这个问题在 Stackoverflow 上被问了很多，但我还没有找到一个可以解决我遇到的问题的问题。另外，很高兴看到关于更好的方法的想法。

目前，如果一天是关闭的(在这个例子中是星期天)或者如果是“星期六”凌晨 1 点(从技术上讲是星期天早上 1 点)，它就会中断。我有一种感觉，我必须更改数据的存储方式以应对午夜之后的情况，但我正在尝试使用我现在拥有的东西。这是个问题，因为大多数餐厅将特定日期的营业时间列为下午 5 点至凌晨 2 点，而不是下午 5 点至中午 12 点、中午 12 点至凌晨 2 点。

无论如何，这就是我所拥有的。请告诉我更好的方法。

我有这样存储的时间:

$times = array(
    'opening_hours_mon' => '9am - 8pm',
    'opening_hours_tue' => '9am - 2am',
    'opening_hours_wed' => '8:30am - 2am',
    'opening_hours_thu' => '5:30pm - 2am',
    'opening_hours_fri' => '8:30am - 11am',
    'opening_hours_sat' => '9am - 3pm, 5pm - 2am',
    'opening_hours_sun' => 'closed'
);

这是我现在使用的代码:

// Get the right key for today
$status = 'open';
$now = (int) current_time( 'timestamp' );
$day = strtolower( date('D', $now) );
$string = 'opening_hours_'.$day;

$times = $meta[$string][0]; // This should be a stirng like '6:00am - 2:00am' or even '6:00am - 11:00am, 1:00pm to 11:00pm'.

// Does it contain a '-', if not assume it's closed.
$pos = strpos($times, '-');
if ($pos === false) {       
    $status = 'closed';
} else {

    // Maybe a day has multiple opening times?
    $seating_times = explode(',', $times);
    foreach( $seating_times as $time ) {

        $chunks = explode('-', $time);
        $open_time = strtotime($chunks[0]);
        $close_time = strtotime($chunks[1]);

        // Calculate if now is between range of open and closed
        if(($open_time <= $now) && ($now <= $close_time)) {
            $status = 'open';
            break;
        } else {
            $status = 'closed';             
        }

    }

}

注:current_time('timestamp',0) is a WordPress function .

Answer 1

这是我的面向对象的解决方案，基于 PHP DateTime class 的用法(5.2版本后可用):

<?php 

class Restaurant {
    private $cw;
    private $times = array();
    private $openings = array();

    public function __construct(array $times) {
        $this->times = $times;
        $this->setTimes(date("w") ? "this" : "last");
        //print_r($this->openings);       // Debug
    }

    public function setTimes($cw) {
        $this->cw = $cw;
        foreach ($this->times as $key => $val) {
            $t = array();
            $buf = strtok($val, ' -,');
            for ($n = 0; $buf !== FALSE; $n++) {
                try {
                    $d = new DateTime($buf);
                    $d->setTimestamp(strtotime(substr($key, -3)." {$this->cw} week {$buf}"));
                    if ($n && ($d < $t[$n-1])) {
                        $d->add(new DateInterval('P1D'));
                    }
                    $t[] = $d;
                } catch (Exception $e) {
                    break;
                }
                $buf = strtok(' -,');
            }
            if ($n % 2) {
                throw new Exception("Invalid opening time: {$val}");
            } else {
                $this->openings[substr($key, -3)] = $t;
            }
        }
    }

    public function isOpen() {
        $cw = date("w") ? "this" : "last";
        if ($cw != $this->cw) {
            $this->setTimes($cw);
        }
        $d = new DateTime('now');
        foreach ($this->openings as $wd => $t) {
            $n = count($t);
            for ($i = 0; $i < $n; $i += 2) {
                if (($d >= $t[$i]) && ($d <= $t[$i+1])) {
                    return(TRUE);
                }
            }
        }
        return(FALSE);
    }
}

$times = array(
    'opening_hours_mon' => '9am - 8pm',
    'opening_hours_tue' => '9am - 2am',
    'opening_hours_wed' => '8:30am - 2am',
    'opening_hours_thu' => '9am - 3pm',
    'opening_hours_fri' => '8:30am - 11am',
    'opening_hours_sat' => '9am - 3pm, 5pm - 2am',
    'opening_hours_sun' => 'closed'
);

try {
    $r = new Restaurant($times);
    $status = $r->isOpen() ? 'open' : 'closed';
    echo "status=".$status.PHP_EOL;
} catch (Exception $e) {
    echo $e->getMessage().PHP_EOL;
}

?>

如您所见，构造函数构建了一个内部表单(DateTime 对象的 openings 数组)，然后在 isOpen 方法中使用它进行简单比较以检查打电话时餐厅是开门还是关门。

您还会注意到我使用了 DateTime:add计算明天日期的方法，而不是将 86400 (24*60*60) 添加到当前日期时间戳，以避免 DST 出现问题时移。
概念验证:

<?php

ini_set("date.timezone", "Europe/Rome");
echo "date.timezone = ".ini_get("date.timezone").PHP_EOL;

$d1 = strtotime("2013-10-27 00:00:00");
$d2 = strtotime("2013-10-28 00:00:00");
// Expected: 86400, Result: 90000
echo "Test #1: ".($d2 - $d1).PHP_EOL;
// Expected: 2013-10-28 00:00:00, Result: 2013-10-27 23:00:00
echo "Test #2: ".date("Y-m-d H:i:s", $d1 + 86400).PHP_EOL;

$d1 = strtotime("2014-03-30 00:00:00");
$d2 = strtotime("2014-03-31 00:00:00");
// Expected: 86400, Result: 82800
echo "Test #3: ".($d2 - $d1).PHP_EOL;
// Expected: 2014-03-30 00:00:00, Result: 2014-03-29 23:00:00
echo "Test #4: ".date("Y-m-d H:i:s", $d2 - 86400).PHP_EOL;

?>

结果如下:

date.timezone = Europe/Rome
Test #1: 90000
Test #2: 2013-10-27 23:00:00
Test #3: 82800
Test #4: 2014-03-29 23:00:00

因此，一天似乎并不总有86400秒；至少一年两次...