php 从日期字符串中获取时间

Question

我正在尝试获取两个日期时间字符串之间传递的时间(包括毫秒)

例子:

$pageTime = strtotime("2012-04-23T16:08:14.9-05:00");
$rowTime = strtotime("2012-04-23T16:08:16.1-05:00");
$timePassed = $rowTime - $pageTime;
echo $timePassed . "<br/><br/>";

我希望看到的回显是“1.2”，但是 strtotime() 忽略了字符串的毫秒部分。此外，显然 microtime() 不允许你给它一个日期字符串......是否有一个替代函数来计算这个，或者我是否必须做一些字符串解析来提取秒数和毫秒和减法？

Answer 1

试试 DateTime相反。

这需要一些解决方法，因为 DateInterval(由 DateTime::diff() 返回)不计算微秒，所以您需要这样做手工

$pageTime = new DateTime("2012-04-23T16:08:14.1 - 5 hours");
$rowTime  = new DateTime("2012-04-23T16:08:16.9 - 5 hours");

// the difference through one million to get micro seconds
$uDiff = abs($pageTime->format('u')-$rowTime->format('u')) / (1000 * 1000);

$diff = $pageTime->diff($rowTime);

echo $diff->format('%s')-$uDiff;

我总是推荐 DateTime 因为它的灵 active ，你应该研究一下

编辑

为了向后兼容 PHP 5.2，它采用与毫秒相同的方法:

$pageTime = new DateTime("2012-04-23T16:08:14.1 - 5 hours");
$rowTime  = new DateTime("2012-04-23T16:08:16.9 - 5 hours");

// the difference through one million to get micro seconds
$uDiff = abs($pageTime->format('u')-$rowTime->format('u')) / (1000 * 1000);


$pageTimeSeconds = $pageTime->format('s');
$rowTimeSeconds  = $rowTime->format('s');

if ($pageTimeSeconds + $rowTimeSeconds > 60) {
  $sDiff = ($rowTimeSeconds + $pageTimeSeconds)-60;
} else {
  $sDiff = $pageTimeSeconds - $rowTimeSeconds;
}


if ($sDiff < 0) {
  echo abs($sDiff) + $uDiff;
} else {
  // for the edge(?) case if $dt2 was smaller than $dt
  echo abs($sDiff - $uDiff);
}