php - 警告 : Cannot use a scalar value as an array in

Question

我在执行状态脚本时看到以下错误:

Warning: Cannot use a scalar value as an array in 

$result[$array[$i*2]] = $array[$i*2+1];

我做错了什么？我在下面包含了完整的代码:

<?php 

// Set the host and port 
$host = "ip_goes_here"; 
$port = port_goes_here; 

// Open the socket connection to the server 
$fp = fsockopen("udp://".$host, $port); 

// Set the string to send to the server 
$string = "\xff\xff\xff\xffgetinfo"; 

// Set the socket timeout to 2 seconds 
socket_set_timeout($fp, 2); 

// Actually send the string 
fwrite($fp, $string); 

// Read the first 18 bytes to get rid of the header and do the error checking here 
if(!fread($fp, 18)) { 

      die("Oh God, the pain!"); 
} 

// Get the status of the socket, to be used for the length left 
$status = socket_get_status($fp); 

// Read the rest 
$info = fread($fp, $status['unread_bytes']); 

// Explode the result of the fread into another variable 
$array = explode("\\", $info); 

// Loop through and create a result array, with the key being even, the result, odd 
for($i = 0; $i < count($array)/2; $i++) { 

    $result[$array[$i*2]] = $array[$i*2+1];
} 

// Print the result for error checking 
print_r($result);     

// Close the file pointer 
fclose($fp); 

我提到的行导致了错误。我不知道我在这里做错了什么......

Answer 1

您可以尝试在使用变量$result 之前将其声明为数组。

$result = array();
// Loop through and create a result array, with the key being even, the result, odd 
for($i = 0; $i < count($array)/2; $i++) { 

    $result[$array[$i*2]] = $array[$i*2+1];
}