php - 如何使用PHP获取假期日期

Question

例如:

1. 一月的第三个星期一马丁·路德·金日
2. 2 月的第三个星期一 总统日(华盛顿诞辰日)
3. 三月的最后一个星期日 复活节
4. 5 月的最后一个星期一 阵亡将士纪念日

我正在尝试获取这些日期，这样我就可以在我的日历上标记它，而无需手动放置 future 几年的所有内容。

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修改后的答案!!

$curYir = date("Y");//current year

$MLK = date('Y-m-d', strtotime("january $curYir third monday")); //marthin luthor king day
$PD = date('Y-m-d', strtotime("february $curYir third monday")); //presidents day
$Est =  date('Y-m-d', easter_date($curYir))); // easter 
$MDay = date('Y-m-d', strtotime("may $curYir first monday")); // memorial day
//("may $curYir last monday") will give you the last monday of may 1967
//much better to determine it by a loop
      $eMDay = explode("-",$MDay);
      $year = $eMDay[0];
      $month = $eMDay[1];
      $day = $eMDay[2];

      while($day <= 31){
          $day = $day + 7;
      }
      if($day > 31)
      $day = $day - 7;

      $MDay = $year.'-'.$month.'-'.$day;
$LD = date('Y-m-d', strtotime("september $curYir first monday"));  //labor day
$CD = date('Y-m-d', strtotime("october $curYir third monday")); //columbus day
$TH = date('Y-m-d', strtotime("november $curYir first thursday")); // thanks giving 
//("november $curYir last thursday") will give you the last thursday of november 1967
//much better to determine it by a loop
      $eTH = explode("-",$TH);
      $year = $eTH[0];
      $month = $eTH[1];
      $day = $eTH[2];

      while($day <= 30){
          $day = $day + 7;
      }
      if($day > 30)
      //watch out for the days in the month November only have 30
      $day = $day - 7;

      $TH = $year.'-'.$month.'-'.$day;

Answer 1

您可以利用 php 的这个功能。 strtotime

$currentYear = date("Y");

MLK 日 -

echo date('Y-m-d', strtotime("third monday of january $currentYear"));

总统日 -

echo date('Y-m-d', strtotime("third monday/OD February $currentYear"));

复活节 -

echo date('Y-m-d', strtotime("last sunday of march $currentYear"));

阵亡将士纪念日 -

echo date('Y-m-d', strtotime("last monday of may $currentYear"));