php - 如何使用 curl GET 而不是 POST

Question

我正在尝试使用 curl 来打印来自 url 的返回。到目前为止，我的代码如下所示:

<?php
    $street = $_GET['street'];
    $city = $_GET['city'];
    $state = $_GET['state'];
    $zip = $_GET['zip'];

    $url = 'http://eligibility.cert.sc.egov.usda.gov/eligibility/eligibilityservice';
    $query = 'eligibilityType=Property&requestString=<?xml version="1.0"?><Eligibility xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="/var/lib/tomcat5/webapps/eligibility/Eligibilitywsdl.xsd"><PropertyRequest StreetAddress1="'.$street.'" StreetAddress2="" StreetAddress3="" City="'.$city.'" State="'.$state.'" County="" Zip="'.$zip.'" Program="RBS"></PropertyRequest></Eligibility>';
    $url_final = $url.''.$url_query;

    $ch = curl_init();

    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_POSTFIELDS,$query);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

    $return = curl_exec ($ch);
    curl_close ($ch);

    echo $return;

?>

我所知道的唯一明显的问题是被查询的服务器使用 GET 而不是 POST。此方法是否有 GET 替代方法？

Answer 1

curl_setopt($ch, CURLOPT_POST, 0);

Curl 默认使用 GET。您将其设置为 POST。如果需要，您可以使用 curl_setopt($ch, CURLOPT_HTTPGET, 1);

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