gpt4 book ai didi

PHP电子邮件表单发件人名称而不是电子邮件?

转载 作者:IT王子 更新时间:2023-10-28 23:49:23 27 4
gpt4 key购买 nike

现在,我已经设置了一个 PHP 电子邮件表单并且一切正常。但是,在测试时,我只得到发件人电子邮件地址作为名称。我想要的是发件人的姓名,例如:

李四

主题主题主题

代替:

j.doe@website.com

主题主题主题

下面是代码...

有人可以帮帮我吗?谢谢。

PHP:

<?php
if(isset($_POST['email'])) {

// EDIT THE 2 LINES BELOW AS REQUIRED
$email_to = "ricky@rickytsang.ca";
$email_subject = $_REQUEST['subject'];


function died($error) {
// your error code can go here
echo "We are very sorry, but there were error(s) found with the form you submitted. ";
echo "These errors appear below.<br /><br />";
echo $error."<br /><br />";
echo "Please go back and fix these errors.<br /><br />";
die();
}

// validation expected data exists
if(!isset($_POST['full_name']) ||
!isset($_POST['email']) ||
!isset($_POST['subject']) ||
!isset($_POST['message'])) {
died('We are sorry, but there appears to be a problem with the form you submitted.');
}

$full_name = $_POST['full_name']; // required
$email_from = $_POST['email']; // required
$subject = $_POST['subject'];
$message= $_POST['message']; // required

$error_message = "";
$email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';
if(!preg_match($email_exp,$email_from)) {
$error_message .= 'The e-mail you entered does not appear to be valid.<br />';
}
$string_exp = "/^[A-Za-z .'-]+$/";
if(!preg_match($string_exp,$full_name)) {
$error_message .= 'The name you entered does not appear to be valid.<br />';
}
if(strlen($message) < 2) {
$error_message .= 'The message you entered doee not appear to be valid.<br />';
}
if(strlen($error_message) > 0) {
died($error_message);
}
$email_message = "Form details below.\n\n";

function clean_string($string) {
$bad = array("content-type","bcc:","to:","cc:","href");
return str_replace($bad,"",$string);
}

$email_message .= "Full Name: ".clean_string($full_name)."\n";
$email_message .= "E-mail: ".clean_string($email_from)."\n";
$email_message .= "Subject: ".clean_string($subject)."\n";
$email_message .= "Message: ".clean_string($message)."\n";


// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_from."\r\n" .
'X-Mailer: PHP/' . phpversion();
@mail($email_to, $email_subject, $email_message, $headers);
?>

<!-- include your own success html here -->

Thank you for contacting us. We will be in touch with you very soon.

<?php
}
?>

最佳答案

在您的 4 行 $email_message .= ... 之后添加一行:

$email_from = $full_name.'<'.$email_from.'>';

关于PHP电子邮件表单发件人名称而不是电子邮件?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6728361/

27 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com