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sql - MySQL 错误 1248 (42000) : Every derived table must have its own alias

转载 作者:IT王子 更新时间:2023-10-28 23:45:49 28 4
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我这辈子都想不通为什么会出错

SELECT * FROM 
SELECT
c.city_id,
p.prop_ynow_id,
p.propertyid,
p.prop_add_value,
p.name,
picture,
ifnull(p.address,'') as`location`,
ifnull(city,'')as`city`,
ifnull(ShortCut,'') as `state`,
ifnull(p.zip,'') as `zip`,
min(if(pr.minrent = 0,99999999,pr.minrent)) as minrent,
max(pr.maxrent) as maxrent,
'' as service,
hood_id,
ifnull(p.phone,'') as `phone`,
latitude,
longitude,
min(CAST(pu.fullBath AS UNSIGNED)) as`minbath`,
max(CAST(pu.fullBath AS UNSIGNED)) as`maxbath`,
min(CAST(pu.Bed AS UNSIGNED)) as`minbed` ,
max(CAST(pu.Bed AS UNSIGNED)) as`maxbed`,
'' as url,
'' as source_id,
'' as source_name,
'' as addresscode,
'' as citycode,
'' as ctime,
'' as paid,
'' as similar_url,
'' as created_at,
'' as updated_at,
'' as city_name,
'' as service_listing_id

FROM
wiki_city_list c join propertyinfo p on c.city_id=p.city
join ynow_rentwiki.Property_Unitlayout pu on p.prop_ynow_id=pu.P_Ident
join (SELECT CAST(substring_index(if(Rent >0 ,Rent,RentLow),'.',1) AS UNSIGNED) as minrent, CAST(substring_index(if(Rent >0,Rent,Renthigh),'.',1) AS UNSIGNED) as maxrent,PRE_Ident,P_Ident,UNL_Ident,RTY_Ident from ynow_rentwiki.Property_rents where P_Ident in (3958, 4576, 4577) and (Rent!='' or (Rentlow!='' and Renthigh!='')) ) as pr on pu.UNL_Ident=pr.UNL_Ident
join state s on (p.state = s.stateid OR p.state = s.ShortCut )
WHERE
pu.Status='Active'
and p.delete_date='0000-00-00'

GROUP BY
c.city_id, p.prop_ynow_id

UNION
SELECT
c.city_id,
p.prop_ynow_id,
p.propertyid,
p.prop_add_value,
p.name,
picture,
ifnull(p.address,'') as`location`,
ifnull(city,'')as`city`,
ifnull(ShortCut,'') as `state`,
ifnull(p.zip,'') as `zip`,
min(if(pr.minrent = 0,99999999,pr.minrent)) as minrent,
max(pr.maxrent) as maxrent,
'' as service,
hood_id,
ifnull(p.phone,'') as `phone`,
latitude,
longitude,
min(CAST(pu.fullBath AS UNSIGNED)) as`minbath`,
max(CAST(pu.fullBath AS UNSIGNED)) as`maxbath`,
min(CAST(pu.Bed AS UNSIGNED)) as`minbed` ,
max(CAST(pu.Bed AS UNSIGNED)) as`maxbed`,
'' as url,
'' as source_id,
'' as source_name,
'' as addresscode,
'' as citycode,
'' as ctime,
'' as paid,
'' as similar_url,
'' as created_at,
'' as updated_at,
'' as city_name,
'' as service_listing_id

FROM
wiki_city_list c join propertyinfo p on c.city_id=p.city
join ynow_rentwiki.Property_Unitlayout pu on p.prop_ynow_id=pu.P_Ident
join (SELECT CAST(substring_index(if(Rent >0 ,Rent,RentLow),'.',1) AS UNSIGNED) as minrent, CAST(substring_index(if(Rent >0,Rent,Renthigh),'.',1) AS UNSIGNED) as maxrent,PRE_Ident,P_Ident,UNL_Ident,RTY_Ident from ynow_rentwiki.Property_rents where P_Ident in (9744) and (Rent!='' or (Rentlow!='' and Renthigh!='')) ) as pr on pu.UNL_Ident=pr.UNL_Ident
join state s on (p.state = s.stateid OR p.state = s.ShortCut )
WHERE
pu.Status='Active'
and p.delete_date='0000-00-00'

GROUP BY
c.city_id, p.prop_ynow_id

UNION
SELECT
'' as prop_ynow_id,
id as propertyid,
0 as prop_add_value,
t.name as name,
'' as picture,
t.address as location,
t.city as city,
s.ShortCut as state,
t.zip as zip,
CAST(REPLACE(REPLACE(t.price,'$',''),',','') as UNSIGNED) as minrent,
'' as maxrent,
t.service as service,
'' as hood_id,
'' as phone,
t.latitude as latitude,
t.longitude as longitude,
t.bathrooms as minbath,
'' as maxbath,
t.bedrooms as minbed,
'' as maxbed,
t.url as url,
t.source_id as source_id,
t.source_name as source_name,
t.addresscode as addresscode,
t.citycode as citycode,
t.ctime as ctime,
t.paid as paid,
t.similar_url as similar_url,
t.created_at as created_at,
t.updated_at as updated_at,
SUBSTRING_INDEX(c.city_name,'_',1) as city_name,
t.service_listing_id as service_listing_id

FROM LBCPrimary.third_party_properties as t, LBCPrimary.wiki_city_list as c, LBCPrimary.state as s
WHERE
t.city in ( '230' )
and
address <> '' and
t.city = c.city_id and
c.city_state = s.stateid

order by t.ctime
desc
limit 46 as a limit 0,50

最佳答案

这正是它所说的 - 每个派生表必须有一个别名。 SELECT a.* FROM (SELECT ....)a

更新。这应该适合你:

SELECT xxx.* FROM 
(
SELECT ....
FROM ....
UNION
(
SELECT ....
FROM .....
LIMIT 46
)
LIMIT 50
)xxx

关于sql - MySQL 错误 1248 (42000) : Every derived table must have its own alias,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3363918/

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