mysql - 如何在 SQL 中计算斜率

Question

我在 sql 数据库中有一些数据，我想计算斜率。数据有这样的布局:

Date        |  Keyword  |  Score    
2012-01-10  |  ipad     |  0.12    
2012-01-11  |  ipad     |  0.17    
2012-01-12  |  ipad     |  0.24    
2012-01-10  |  taco     |  0.19    
2012-01-11  |  taco     |  0.34    
2012-01-12  |  taco     |  0.45    

我希望通过使用 SQL 创建一个新表，最终输出看起来像这样:

Date        |  Keyword  |  Score |  Slope    
2012-01-10  |  ipad     |  0.12  |  0.06    
2012-01-11  |  ipad     |  0.17  |  0.06    
2012-01-12  |  ipad     |  0.24  |  0.06    
2012-01-10  |  taco     |  0.19  |  0.13    
2012-01-11  |  taco     |  0.34  |  0.13    
2012-01-12  |  taco     |  0.45  |  0.13

更复杂的是，并非所有关键字都有 3 个日期的数据，例如有些只有 2 个。

SQL 越简单越好，因为我的数据库是专有的，我不太确定有哪些公式可用，尽管我知道如果有帮助的话它可以做 OVER(PARTITION BY)。谢谢!

更新:我将斜率定义为最适合 y=mx+p 在 excel 中也就是 =slope()

这是我通常在 excel 中操作的另一个实际示例:

date        keyword         score       slope   
1/22/2012   water bottle    0.010885442 0.000334784  
1/23/2012   water bottle    0.011203949 0.000334784  
1/24/2012   water bottle    0.008460835 0.000334784  
1/25/2012   water bottle    0.010363991 0.000334784  
1/26/2012   water bottle    0.011800716 0.000334784  
1/27/2012   water bottle    0.012948411 0.000334784  
1/28/2012   water bottle    0.012732459 0.000334784  
1/29/2012   water bottle    0.011682568 0.000334784  

Answer 1

我能做的最干净的一个:

SELECT
    Scores.Date, Scores.Keyword, Scores.Score,
    (N * Sum_XY - Sum_X * Sum_Y)/(N * Sum_X2 - Sum_X * Sum_X) AS Slope
FROM Scores
INNER JOIN (
    SELECT
        Keyword,
        COUNT(*) AS N,
        SUM(CAST(Date as float)) AS Sum_X,
        SUM(CAST(Date as float) * CAST(Date as float)) AS Sum_X2,
        SUM(Score) AS Sum_Y,
        SUM(CAST(Date as float) * Score) AS Sum_XY
    FROM Scores
    GROUP BY Keyword
) G ON G.Keyword = Scores.Keyword;

它使用 Simple Linear Regression计算斜率。

结果:

Date         Keyword        Score         Slope
2012-01-22   water bottle   0,010885442   0,000334784345222076
2012-01-23   water bottle   0,011203949   0,000334784345222076
2012-01-24   water bottle   0,008460835   0,000334784345222076
2012-01-25   water bottle   0,010363991   0,000334784345222076
2012-01-26   water bottle   0,011800716   0,000334784345222076
2012-01-27   water bottle   0,012948411   0,000334784345222076
2012-01-28   water bottle   0,012732459   0,000334784345222076
2012-01-29   water bottle   0,011682568   0,000334784345222076

每个数据库系统似乎都有不同的方法将日期转换为数字:

• MySQL: TO_SECONDS(date) 或 TO_DAYS(date)
• Oracle: TO_NUMBER(TO_CHAR(date, 'J')) 或 date - TO_DATE('1','yyyy')
• MS SQL Server: CAST(date AS float)(或等效的CONVERT)