php - '大于或等于'和 'less than or equal' CODEIGNITER

Question

我必须使用 >= 查询具有 where 条件的内容。和 =<但我没有运气。这在 CODEIGNITER 中。

这是mysql查询中的自然方式:

SELECT COUNT(payment.keyid) AS rec_count, `product_key`.`client_name`, 
`product_key`.`contact_email`, `product_key`.`status`, `product_key`.`id`, 
`payment`.`paymentdate`, (payment.id) as pid, `payment`.`subscription_type` 
FROM (`product_key`) 
LEFT OUTER JOIN `payment` ON `payment`.`keyid`=`product_key`.`id` 
WHERE `payment`.`paymentdate` >= '2013-08-01' 
    AND `payment`.`paymentdate` =< '2013-08-31' 
    AND `status` = 'purchased' 
GROUP BY `product_key`.`id` 
ORDER BY `client_name` asc

这就是我所拥有的:

    return $this->db
    ->select('COUNT(payment.keyid) AS rec_count')
    ->select('product_key.client_name, product_key.contact_email, product_key.status, product_key.id, payment.paymentdate, (payment.id) as pid,payment.subscription_type')
    ->from('product_key')          
    ->where('payment.paymentdate >=', $month_start)
    ->where('payment.paymentdate =<', $month_end)
    ->where('status', 'purchased')
    ->join('payment', 'payment.keyid=product_key.id', 'left outer')
    ->order_by('client_name', "asc")
    ->group_by('product_key.id')
    ->get()
    ->result(); 

也许有人可以在这方面帮助我。谢谢。

Answer 1

更改 =<至<= .

我还在 phpmyadmin 中测试了您当前的查询，因为我不敢相信它不会引发错误。但我的做到了。所以你的查询不应该在 phpmyadmin 中工作。

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '=< ...' at line ...