php - 给出警告 : mysql_num_rows() expects parameter 1 to be resource, 对象

Question

这个问题在这里已经有了答案:

Can I mix MySQL APIs in PHP? (4 个回答)

关闭 去年。

$q="SELECT * FROM tbl_quevote WHERE que_id = '".$qid."' and voteby='".$uid."'";

$result = $mysqli->query($q) or die(mysqli_error($mysqli));
$num_rows = mysql_num_rows($result);

echo $num_rows;

错误:

Warning: mysql_num_rows() expects parameter 1 to be resource, object given in C:\xampp\htdocs\shizin\voting.php on line 13

如何判断结果为空？

Answer 1

$num_rows = $result->num_rows;