gpt4 book ai didi

php - 限制分页页码

转载 作者:IT老高 更新时间:2023-10-29 00:02:13 24 4
gpt4 key购买 nike

$objConnect = mysql_connect("localhost","root","") or die(mysql_error());
$objDB = mysql_select_db("Test");

$strSQL = "SELECT * FROM UserAddedRecord WHERE (Name LIKE '%".$getname."%' and State LIKE '%".$getstate."%' and Cell LIKE '%".$getcell."%' and Custgroup LIKE '%".$getgroup."%') AND user_id=$id";

$objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]");
$Num_Rows = mysql_num_rows($objQuery);

$Per_Page = 5;

if (!isset($_GET['Page'])) {
$Page = 1;
} else {
$Page = $_GET['Page'];
}

$Prev_Page = $Page - 1;
$Next_Page = $Page + 1;

$Page_Start = (($Per_Page * $Page) - $Per_Page);
if ($Num_Rows <= $Per_Page) {
$Num_Pages = 1;
} elseif (($Num_Rows % $Per_Page) == 0) {
$Num_Pages = ($Num_Rows / $Per_Page) ;
} else {
$Num_Pages = ($Num_Rows / $Per_Page) + 1;
$Num_Pages = (int) $Num_Pages;
}


$strSQL .=" order by addedrec_ID DESC LIMIT $Page_Start , $Per_Page";
$objQuery = mysql_query($strSQL) or trigger_error(mysql_error());;

if ($Prev_Page) {
echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$Prev_Page&txtName=$getname&txtState=$getstate&txtCell=$getcell&txtGroup=$getgroup'><< Back</a> ";
}

for ($i=1; $i <= $Num_Pages; $i++) {
if ($i != $Page) {
echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$i&txtName=$getname&txtState=$getstate&txtCell=$getcell&txtGroup=$getgroup'>$i</a> ";
} else {
echo "<b> $i </b>";
}
}

if ($Page!=$Num_Pages) {
echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$Next_Page&txtName=$getname&txtState=$getstate&txtCell=$getcell&txtGroup=$getgroup'>Next>></a> ";
}

mysql_close($objConnect);

这是我用来为数据搜索创建分页页面的代码。但我只是注意到我有太多记录然后它会有太多页码。我试图限制显示的页码,并寻找很多例子..它有很多方法可以做到,但我仍然不知道如何限制我的方法...

最佳答案

好吧,如果你的意思是显示类似的东西

Prev 1 2 3 4 5 6 .. 40 41 Next 
Prev 1 2 .. 6 7 8 9 10 .. 40 41 Next

首先我们需要创建一个函数来处理我们需要输出分页的内容。这是我使用的一个功能,效果很好。

function get_paging_info($tot_rows,$pp,$curr_page)
{
$pages = ceil($tot_rows / $pp); // calc pages

$data = array(); // start out array
$data['si'] = ($curr_page * $pp) - $pp; // what row to start at
$data['pages'] = $pages; // add the pages
$data['curr_page'] = $curr_page; // Whats the current page

return $data; //return the paging data

}

现在这个功能非常可靠,对我来说效果很好。

所以你传递了这个函数

  • $tot_rows = 查询的计数行
  • $pp = 每页的项目数
  • $curr_page = 当前页码

好的,现在您有了所需的数据,您需要显示它。

这是我使用的内容,请在您认为“啊,太长了”之前先阅读它。其实很简单。

这是它将返回的快照

enter image description here

    <!-- Create the query -->
<?php $count = mysql_fetch_assoc( mysql_query ( "SELECT COUNT( rows ) as count FROM table" ) ) ;

<?php $count = $count[0]['count']; ?>

<!-- Call our function from above -->
<?php $paging_info = get_paging_info($count,5,34); ?>


<p>
<!-- If the current page is more than 1, show the First and Previous links -->
<?php if($paging_info['curr_page'] > 1) : ?>
<a href='' title='Page 1'>First</a>
<a href='' title='Page <?php echo ($paging_info['curr_page'] - 1); ?>'>Prev</a>
<?php endif; ?>



<?php
//setup starting point

//$max is equal to number of links shown
$max = 7;
if($paging_info['curr_page'] < $max)
$sp = 1;
elseif($paging_info['curr_page'] >= ($paging_info['pages'] - floor($max / 2)) )
$sp = $paging_info['pages'] - $max + 1;
elseif($paging_info['curr_page'] >= $max)
$sp = $paging_info['curr_page'] - floor($max/2);
?>

<!-- If the current page >= $max then show link to 1st page -->
<?php if($paging_info['curr_page'] >= $max) : ?>

<a href='' title='Page 1'>1</a>
..

<?php endif; ?>

<!-- Loop though max number of pages shown and show links either side equal to $max / 2 -->
<?php for($i = $sp; $i <= ($sp + $max -1);$i++) : ?>

<?php
if($i > $paging_info['pages'])
continue;
?>

<?php if($paging_info['curr_page'] == $i) : ?>

<span class='bold'><?php echo $i; ?></span>

<?php else : ?>

<a href='' title='Page <?php echo $i; ?>'><?php echo $i; ?></a>

<?php endif; ?>

<?php endfor; ?>


<!-- If the current page is less than say the last page minus $max pages divided by 2-->
<?php if($paging_info['curr_page'] < ($paging_info['pages'] - floor($max / 2))) : ?>

..
<a href='' title='Page <?php echo $paging_info['pages']; ?>'><?php echo $paging_info['pages']; ?></a>

<?php endif; ?>

<!-- Show last two pages if we're not near them -->
<?php if($paging_info['curr_page'] < $paging_info['pages']) : ?>

<a href='<?php echo str_replace('/page'.$paging_info['curr_page'], '', $paging_info['curr_url']) . '/page'.($paging_info['curr_page'] + 1); ?>' title='Page <?php echo ($paging_info['curr_page'] + 1); ?>'>Next</a>

<a href='<?php echo str_replace('/page'.$paging_info['curr_page'], '', $paging_info['curr_url']) . '/page'.$paging_info['pages']; ?>' title='Page <?php echo $paging_info['pages']; ?>'>Last</a>

<?php endif; ?>
</p>

关于php - 限制分页页码,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8361808/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com