c++ - 我可以将 Unresolved 引用链接到中止吗？

Question

我正在尝试为一个相当大的项目的一小部分编写一些小测试。不幸的是，如果不将整个项目链接在一起，尝试链接这个野兽是相当不可能的，我不想这样做(这是一个非常复杂的系统，用于查找所有依赖项和东西，我不喜欢干预它)。

现在，我确定在我的测试期间不会调用引用函数的函数，只是恰好是与我测试的东西共享文件的函数的一部分。

有什么方法可以简单地将这些未解析的引用链接到，比如说，中止或其他什么？或者是否有一个工具可以创建适当的 stub 对象文件，其中所有调用都会导致中止，给定我拥有的一组对象文件？

我使用 gcc (g++) 进行编译/链接，版本 3.4.4。平台是 unix(如果这很重要，则为 solaris/sparc)。

Answer 1

您可以告诉链接器忽略未解析的符号。我找不到将它们链接到 abort 或类似内容的选项。

我认为，仅忽略目标文件中未解析符号的策略是最自然的:

gcc -Wl,--unresolved-symbols=ignore-in-object-files  obj.o another.o etc.o

其他选项包括(引用 man ld):

   --unresolved-symbols=method
       Determine how to handle unresolved symbols.  There are four possi-
       ble values for method:

       ignore-all
           Do not report any unresolved symbols.

       report-all
           Report all unresolved symbols.  This is the default.

       ignore-in-object-files
           Report  unresolved  symbols  that  are  contained  in   shared
           libraries,  but  ignore  them if they come from regular object
           files.

       ignore-in-shared-libs
           Report unresolved symbols that come from regular object files,
           but  ignore them if they come from shared libraries.  This can
           be useful when creating a dynamic binary and it is known  that
           all  the  shared  libraries  that it should be referencing are
           included on the linker's command line.

       The behaviour for shared libraries on their own can also  be  con-
       trolled by the --[no-]allow-shlib-undefined option.

       Normally  the  linker  will  generate  an  error  message for each
       reported unresolved symbol but the  option  --warn-unresolved-sym-
       bols can change this to a warning.

在我的 Linux 系统上尝试调用未解析的函数会导致“段错误”。