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c++ - C/C++ 无符号整数溢出

转载 作者:IT老高 更新时间:2023-10-28 22:33:40 25 4
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我正在阅读有关整数安全性的文章。这是链接: http://ptgmedia.pearsoncmg.com/images/0321335724/samplechapter/seacord_ch05.pdf

第166页说:

A computation involving unsigned operands can never overflow,because a result that cannot be represented by the resulting unsigned integer type is reduced modulo to the number that is one greater than the largest value that can be represented by the resulting type.

这是什么意思?感谢您的回复。

最佳答案

表示值“环绕”。

UINT_MAX + 1 == 0
UINT_MAX + 2 == 1
UINT_MAX + 3 == 2

..等等

正如链接所说,这就像模运算符:http://en.wikipedia.org/wiki/Modulo_operation

关于c++ - C/C++ 无符号整数溢出,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16056758/

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