c++ - 如何破解虚拟表？

Question

我想知道如何将虚拟表中的Test的地址更改为HackedVTable的地址。

void HackedVtable()
{
    cout << "Hacked V-Table" << endl;
}

class Base
{    
public:
    virtual Test()  { cout <<"base";    }
    virtual Test1() { cout << "Test 1"; }
    void *prt;
    Base(){}
};

class Derived : public Base
{
public: 
    Test()
    {
        cout <<"derived";
    }
};

int main()
{    
    Base b1;

    b1.Test(); // how to change this so that `HackedVtable` should be called instead of `Test`?

    return 0;
}

Answer 1

这适用于 32 位 MSVC 构建(它是一些已使用一年多的生产代码的非常简化的版本)。请注意，您的替换方法必须明确指定 this 参数(指针)。

// you can get the VTable location either by dereferencing the
// first pointer in the object or by analyzing the compiled binary.
unsigned long VTableLocation = 0U;
// then you have to figure out which slot the function is in. this is easy
// since they're in the same order as they are declared in the class definition.
// just make sure to update the index if 1) the function declarations are
// re-ordered and/or 2) virtual methods are added/removed from any base type.
unsigned VTableOffset = 0U;
typedef void (__thiscall Base::*FunctionType)(const Base*);
FunctionType* vtable = reinterpret_cast<FunctionType*>(VTableLocation);

bool hooked = false;
HANDLE process = ::GetCurrentProcess();
DWORD protection = PAGE_READWRITE;
DWORD oldProtection;
if ( ::VirtualProtectEx( process, &vtable[VTableOffset], sizeof(int), protection, &oldProtection ) )
{
    vtable[VTableOffset] = static_cast<FunctionType>(&ReplacementMethod);

    if ( ::VirtualProtectEx( process, &vtable[VTableOffset], sizeof(int), oldProtection, &oldProtection ) )
        hooked = true;
}