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给定:
#include "gmock/gmock.h"
#include <string>
using namespace testing; // tsk, tsk
// -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --
struct Mockable {
virtual std::string ify(int x) const;
};
std::string Mockable::ify(int x) const
{
return std::to_string(x);
}
// -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --
struct Mocked : public Mockable {
MOCK_CONST_METHOD1(ify, std::string(int));
};
// -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --
std::string tested(Mockable const& u, int x)
{
return u.ify(x);
}
TEST(TC,T42)
{
Mocked mock;
ON_CALL(mock, ify(Eq(42)))
.WillByDefault(Return("33"));
std::string const& ret = tested(mock, 42);
EXPECT_EQ("42", ret);
}
TEST(TC,T33)
{
Mocked mock;
ON_CALL(mock, ify(Eq(33)))
.WillByDefault(Return("333"));
std::string const& ret = tested(mock, 42);
EXPECT_EQ("42", ret);
}
int main(int argc, char *argv[])
{
::testing::InitGoogleTest(&argc, argv);
//::testing::FLAGS_gmock_verbose = "info";
return RUN_ALL_TESTS();
}
输出是:
$ ./mocktest
[==========] Running 2 tests from 1 test case.
[----------] Global test environment set-up.
[----------] 2 tests from TC
[ RUN ] TC.T42
GMOCK WARNING:
Uninteresting mock function call - taking default action specified at:
mocktest.cc:40:
Function call: ify(42)
Returns: "33"
Stack trace:
mocktest.cc:44: Failure
Value of: ret
Actual: "33"
Expected: "42"
[ FAILED ] TC.T42 (0 ms)
[ RUN ] TC.T33
GMOCK WARNING:
Uninteresting mock function call - returning default value.
Function call: ify(42)
Returns: ""
Stack trace:
mocktest.cc:54: Failure
Value of: ret
Actual: ""
Expected: "42"
[ FAILED ] TC.T33 (1 ms)
[----------] 2 tests from TC (1 ms total)
[----------] Global test environment tear-down
[==========] 2 tests from 1 test case ran. (1 ms total)
[ PASSED ] 0 tests.
[ FAILED ] 2 tests, listed below:
[ FAILED ] TC.T42
[ FAILED ] TC.T33
在这两种情况下,Gmock 的行为都是正确的。应用行为(或不应用,在 TC33 中)。但是为什么在这两种情况下都说“无趣的模拟函数调用”呢?模拟函数调用是否只有在使用 EXPECT_CALL
指定时才有意义?
最佳答案
"Are mock function calls interesting only when specified with EXPECT_CALL ?"
简而言之,是的。ON_CALL()
宏仅影响要对模拟方法调用执行的操作,而不影响在模拟对象上设置的调用预期。
您可以使用 NiceMock<>
模板,但一般会抑制这些警告。
To cite from google mocks "Cookbook"
Suppose your test uses a mock class MockFoo:
TEST(...) {
MockFoo mock_foo;
EXPECT_CALL(mock_foo, DoThis());
... code that uses mock_foo ...
}
If a method of mock_foo other than DoThis() is called, it will be reported by Google Mock as a warning. However, if you rewrite your test to use NiceMock instead, the warning will be gone, resulting in a cleaner test output:
using ::testing::NiceMock;
TEST(...) {
NiceMock<MockFoo> mock_foo;
EXPECT_CALL(mock_foo, DoThis());
... code that uses mock_foo ...
}
NiceMock<MockFoo>
is a subclass ofMockFoo
, so it can be used whereverMockFoo
is accepted.
关于c++ - 有没有办法用 ON_CALL 制作模拟函数 "interesting"?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26156879/
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