Python/Django : Creating a simpler list from values_list()

Question

考虑:

>>>jr.operators.values_list('id')
[(1,), (2,), (3,)]

如何进一步简化为:

['1', '2', '3']

目的:

class ActivityForm(forms.ModelForm):
    def __init__(self, *args, **kwargs):
        super(ActivityForm, self).__init__(*args, **kwargs)
        if self.initial['job_record']:
            jr = JobRecord.objects.get(pk=self.initial['job_record'])

            # Operators
            self.fields['operators'].queryset = jr.operators

            # select all operators by default
            self.initial['operators'] = jr.operators.values_list('id') # refined as above.

Answer 1

使用 django 查询集的 flat=True 构造:https://docs.djangoproject.com/en/dev/ref/models/querysets/#django.db.models.query.QuerySet.values_list

来自文档中的示例:

>>> Entry.objects.values_list('id', flat=True).order_by('id')
[1, 2, 3, ...]