node.js - NodeJS Express - 两个端口上的单独路由

Question

我有一个快速服务器，在构建它时，在它们自己的路线上创建了几个“帮助”功能。我希望在不同的端口上访问这些路线。有没有办法在 express 中做到这一点？

在下面的代码中，“/factory”路由(和其他功能)将在一个端口上，而“/killallthings”、“/listallthings”和“/killserver”的辅助路由将在一个单独的端口上港口。

下面是简化版的代码:

var express = require('express');
var things = [];
var app = express();
var port = 8080; 

app.post('/factory/', function(req, res) {
  //Create a thing and add it to the thing array
});

//Assume more functions to do to things here....

app.post('/killallthings/', function(req, res) {
  //Destroy all the things in the array
});

app.post('/listallthings/', function(req, res) {
  // Return a list of all the things
});

app.post('/killserver/', function(req,res){
  //Kills the server after killing the things and doing clean up
});

//Assume https options properly setup.

var server = require('https').createServer(options, app);

server.listen(port, function() {
    logger.writeLog('Listening on port ' + port);
});

express 可以做到吗？

Answer 1

根据上面的爆炸药片建议，我大致这样修改了代码:

var express = require('express');
var things = [];
var app = express();
var admin_app = express();
var port = 8080; 
var admin_port = 8081;

app.post('/factory/', function(req, res) {
  //Create a thing and add it to the thing array
});

//Assume more functions to do to things here....

admin_app.post('/killallthings/', function(req, res) {
  //Destroy all the things in the array
});

admin_app.post('/listallthings/', function(req, res) {
  // Return a list of all the things
});

admin_app.post('/killserver/', function(req,res){
  //Kills the server after killing the things and doing clean up
});

//Assume https options properly setup.

var server = require('https').createServer(options, app);

server.listen(port, function() {
    logger.writeLog('Listening on port ' + port);
});

var admin_server = require('https').createServer(options, admin_app);

admin_server.listen(admin_port, function() {
    logger.writeLog('Listening on admin port ' + admin_port);
});

我希望我知道如何将爆炸药丸的答案归功于自己! :)