gpt4 book ai didi

android - ListView 中的自定义过滤 ArrayAdapter

转载 作者:IT老高 更新时间:2023-10-28 21:56:23 27 4
gpt4 key购买 nike

我是 Android 的初学者,但我尝试进行自定义 ListView 过滤,但它以某种方式工作。我唯一的问题是,我保留所有值的 ArrayList (“原始” ArrayList )在每次过滤中的项目上都越来越低。我无法解释这一点,但我认为您可以以某种方式帮助我。

无论如何这里是自定义 ArrayAdaptor:

public class PkmnAdapter extends ArrayAdapter<Pkmn> {

private ArrayList<Pkmn> original;
private ArrayList<Pkmn> fitems;
private Filter filter;

public PkmnAdapter(Context context, int textViewResourceId, ArrayList<Pkmn> items) {
super(context, textViewResourceId, items);
this.original = items;//new ArrayList<Pkmn>();
this.fitems = items;//new ArrayList<Pkmn>();
}

@Override
public void add(Pkmn item){
original.add(item);
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
View v = convertView;
if (v == null) {
LayoutInflater vi = (LayoutInflater)getContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
v = vi.inflate(R.layout.row, null);
}
Pkmn pkmn = original.get(position);
if (pkmn != null) {
TextView tt = (TextView) v.findViewById(R.id.RlabPName);
TextView dex = (TextView)v.findViewById(R.id.RlabDex);
ImageView img = (ImageView)v.findViewById(R.id.RimgPkmn);

if (tt != null) { tt.setText(pkmn.getName()); }
if (dex != null){ dex.setText(CalcDex(pkmn.getId())); }
if (img != null){
int resId = getContext().getResources().getIdentifier("dex" + pkmn.getId(), "drawable", "com.compileguy.pokebwteam");
img.setImageResource(resId);
}
}
return v;
}

@Override
public Filter getFilter()
{
if (filter == null)
filter = new PkmnNameFilter();

return filter;
}

private class PkmnNameFilter extends Filter
{
@Override
protected FilterResults performFiltering(CharSequence constraint)
{
FilterResults results = new FilterResults();
String prefix = constraint.toString().toLowerCase();

if (prefix == null || prefix.length() == 0)
{
ArrayList<Pkmn> list = new ArrayList<Pkmn>(original);
results.values = list;
results.count = list.size();
}
else
{
final ArrayList<Pkmn> list = original;

int count = list.size();
final ArrayList<Pkmn> nlist = new ArrayList<Pkmn>(count);

for (int i=0; i<count; i++)
{
final Pkmn pkmn = list.get(i);
final String value = pkmn.getName().toLowerCase();

if (value.startsWith(prefix))
{
nlist.add(pkmn);
}
}
results.values = nlist;
results.count = nlist.size();
}
return results;
}

@SuppressWarnings("unchecked")
@Override
protected void publishResults(CharSequence constraint, FilterResults results) {
fitems = (ArrayList<Pkmn>)results.values;
clear();
int count = fitems.size();
for (int i=0; i<count; i++)
{
Pkmn pkmn = (Pkmn)fitems.get(i);
add(pkmn);
}

if (fitems.size() > 0)
notifyDataSetChanged();
else
notifyDataSetInvalidated();
}

}


private String CalcDex(int id){
String s = String.valueOf(id);
if (s.length() == 1)
s = "00"+s;
else if (s.length() == 2)
s = "0"+s;
return '#'+s;
}

}

注意: ListView 正确显示了项目,但是当我删除编辑框中的一个字母(触发过滤)时,这就是问题的开始。

--- 编辑 ---

@Janusz:非常感谢您的回答。这解决了我的问题。

这是对我有用的源代码,所以如果有人有同样的问题,他们可以试试这个:

private ArrayList<Pkmn> original;
private ArrayList<Pkmn> fitems;
private Filter filter;

public PkmnAdapter(Context context, int textViewResourceId, ArrayList<Pkmn> items) {
super(context, textViewResourceId, items);
this.original = new ArrayList<Pkmn>(items);
this.fitems = new ArrayList<Pkmn>(items);
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
View v = convertView;
if (v == null) {
LayoutInflater vi = (LayoutInflater)getContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
v = vi.inflate(R.layout.row, null);
}
Pkmn pkmn = fitems.get(position);
if (pkmn != null) {
TextView tt = (TextView) v.findViewById(R.id.RlabPName);
TextView dex = (TextView)v.findViewById(R.id.RlabDex);
ImageView img = (ImageView)v.findViewById(R.id.RimgPkmn);

if (tt != null) { tt.setText(pkmn.getName()); }
if (dex != null){ dex.setText(CalcDex(pkmn.getId())); }
if (img != null){
int resId = getContext().getResources().getIdentifier("dex" + pkmn.getId(), "drawable", "com.compileguy.pokebwteam");
img.setImageResource(resId);
}
}
return v;
}

@Override
public Filter getFilter()
{
if (filter == null)
filter = new PkmnNameFilter();

return filter;
}

private class PkmnNameFilter extends Filter
{
@Override
protected FilterResults performFiltering(CharSequence constraint)
{
FilterResults results = new FilterResults();
String prefix = constraint.toString().toLowerCase();

if (prefix == null || prefix.length() == 0)
{
ArrayList<Pkmn> list = new ArrayList<Pkmn>(original);
results.values = list;
results.count = list.size();
}
else
{
final ArrayList<Pkmn> list = new ArrayList<Pkmn>(original);
final ArrayList<Pkmn> nlist = new ArrayList<Pkmn>();
int count = list.size();

for (int i=0; i<count; i++)
{
final Pkmn pkmn = list.get(i);
final String value = pkmn.getName().toLowerCase();

if (value.startsWith(prefix))
{
nlist.add(pkmn);
}
}
results.values = nlist;
results.count = nlist.size();
}
return results;
}

@SuppressWarnings("unchecked")
@Override
protected void publishResults(CharSequence constraint, FilterResults results) {
fitems = (ArrayList<Pkmn>)results.values;

clear();
int count = fitems.size();
for (int i=0; i<count; i++)
{
Pkmn pkmn = (Pkmn)fitems.get(i);
add(pkmn);
}
}

}
}

最佳答案

你的问题是这几行:

this.original = items;
this.fitems = items;

Items 是您用于 ListView 的列表,将它放在两个不同的变量中不会产生两个不同的列表。您只给列表项两个不同的名称。

你可以使用:

this.fitems = new ArrayList(items);

这应该生成一个新的列表,并且对该列表的更改只会更改 fitems 列表。

关于android - ListView 中的自定义过滤 ArrayAdapter,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6492214/

27 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com