node.js - 如何在 node.js 中删除 "require"之后的模块？

Question

假设我需要一个模块并执行以下操作:

var b = require('./b.js');
--- do something with b ---

然后我想带走模块 b(即清理缓存)。我该怎么做？

原因是我想在不重新启动 Node 服务器的情况下动态加载/删除或更新模块。有什么想法吗？

------- 更多 --------根据删除require.cache的建议，还是不行……

what I did are few things:
1) delete require.cache[require.resolve('./b.js')];
2) loop for every require.cache's children and remove any child who is b.js
3) delete b

但是，当我调用 b 时，它仍然存在!它仍然可以访问。除非我这样做:

b = {};

不确定这是否是处理该问题的好方法。因为如果以后，我需要 ('./b.js') 在 b.js 已被修改时再次。它需要旧的缓存 b.js(我试图删除)还是新的？

-----------更多发现--------------

好的。我做了更多的测试和代码玩弄..这是我发现的:

1) delete require.cache[]  is essential.  Only if it is deleted, 
 then the next time I load a new b.js will take effect.
2) looping through require.cache[] and delete any entry in the 
 children with the full filename of b.js doesn't take any effect.  i.e.
u can delete or leave it.  However, I'm unsure if there is any side
effect.  I think it is a good idea to keep it clean and delete it if
there is no performance impact.
3) of course, assign b={} doesn't really necessary, but i think it is 
 useful to also keep it clean.

Answer 1

您可以使用它来删除它在缓存中的条目:

delete require.cache[require.resolve('./b.js')]

require.resolve() 会计算出./b.js的完整路径，用作缓存键。