c++ - 变量列表中的逗号是序列点吗？

Question

在以下类型的代码中，每个变量构造之间是否存在序列点，或者结果未定义？

int a = 0;
int b = a++, c = a++;

我无法在标准中找到对此处序列点的特定引用。这是否意味着它未定义，或者只是我的搜索失败？表达式的完成是一个序列点，但是上面的初始化也算吗？

Answer 1

我相信由于8[dcl.decl]/3

，行为是明确定义的

Each init-declarator in a declaration is analyzed separately as if it was in a declaration by itself.

这甚至在脚注中额外解释为

A declaration with several declarators is usually equivalent to the corresponding sequence of declarations each with a single declarator. That is

T D1, D2, ... Dn;

is usually equvalent to

T D1; T D2; ... T Dn;