python - 从一组(相似的)字符串中确定前缀

Question

我有一组字符串，例如

my_prefix_what_ever
my_prefix_what_so_ever
my_prefix_doesnt_matter

我只是想找到这些字符串中最长的公共(public)部分，这里是前缀。在上面的结果应该是

my_prefix_

字符串

my_prefix_what_ever
my_prefix_what_so_ever
my_doesnt_matter

应该是前缀

my_

在 Python 中是否有一种相对轻松的方式来确定前缀(无需手动迭代每个字符)？

PS:我使用的是 Python 2.6.3。

Answer 1

永远不要重写提供给您的内容:os.path.commonprefix正是这样做的:

Return the longest path prefix (taken character-by-character) that is a prefix of all paths in list. If list is empty, return the empty string (''). Note that this may return invalid paths because it works a character at a time.

为了与其他答案进行比较，代码如下:

# Return the longest prefix of all list elements.
def commonprefix(m):
    "Given a list of pathnames, returns the longest common leading component"
    if not m: return ''
    s1 = min(m)
    s2 = max(m)
    for i, c in enumerate(s1):
        if c != s2[i]:
            return s1[:i]
    return s1