Android :java. lang.SecurityException:注入(inject)另一个应用程序需要INJECT_EVENTS权限

Question

您好，我是 Android Junit 测试的新手:

我在 MainActivityFunctionalTest.java 文件中编写了一些测试代码

MainActivityFunctionalTest.java:

package com.example.myfirstapp2.test;

public class MainActivityFunctionalTest extends ActivityInstrumentationTestCase2<Login>{

private static final String TAG = "MainActivityFunctionalTest";
private Login activity;

  public MainActivityFunctionalTest() {
    super(Login.class);
  }


  @Override
  protected void setUp() throws Exception {
     Log.d(TAG,"Set-Up");
     super.setUp();
    setActivityInitialTouchMode(false);
    activity = getActivity();
  }

  public void testStartSecondActivity() throws Exception {
      // add monitor to check for the second activity
        ActivityMonitor monitor =
            getInstrumentation().
              addMonitor(DisplayMessageActivity.class.getName(), null, false);
        //addMonitor(MainActivity.class.getName(), null, false);
     // find button and click it
        Button view = (Button) activity.findViewById(R.id.btnLogin);

        // TouchUtils handles the sync with the main thread internally
        TouchUtils.clickView(this, view);

        // to click on a click, e.g., in a listview
        // listView.getChildAt(0);

        // wait 2 seconds for the start of the activity
        DisplayMessageActivity startedActivity = (DisplayMessageActivity) 

     monitor
            .waitForActivityWithTimeout(5000);
        assertNotNull(startedActivity);

        // search for the textView
        TextView textView = (TextView) startedActivity.findViewById(R.id.Email);

        // check that the TextView is on the screen
        ViewAsserts.assertOnScreen(startedActivity.getWindow().getDecorView(),
            textView);
        // validate the text on the TextView
        assertEquals("Text incorrect", "1http://www.vogella.com", 

         textView.getText().toString());

        // press back and click again
        this.sendKeys(KeyEvent.KEYCODE_BACK);

        TouchUtils.clickView(this, view);

  }


    }

但是，我得到一个错误:java.lang.SecurityException:注入(inject)到另一个应用程序需要 INJECT_EVENTS 权限

在 com.example.myfirstapp2.test.MainActivityFunctionalTest.testStartSecondActivity(MainActivityFunctionalTest.java:70)

 TouchUtils.clickView(this, view);

请帮忙

Answer 1

我遇到了同样的问题，我的代码是这样的(对于正常的登录 Activity ):

    onView(withId(R.id.username))
            .perform(new TypeTextAction("test_user"));
    onView(withId(R.id.password))
            .perform(new TypeTextAction("test123"));
    onView(withId(R.id.login)).perform(click());

最后一行因 SecurityException 而崩溃。结果在最后一次输入文本后，键盘保持打开状态，因此下一次点击被认为是在不同的应用程序上。

要解决此问题，我只需在键入后关闭键盘即可。我还必须添加一些 sleep 以确保键盘已关闭，否则测试会不时中断。所以最终的代码是这样的:

    onView(withId(R.id.username))
            .perform(new TypeTextAction("test_user"));
    onView(withId(R.id.password))
            .perform(new TypeTextAction("test123")).perform(closeSoftKeyboard());
    Thread.sleep(250);
    onView(withId(R.id.login)).perform(click());

这工作得很好。