gpt4 book ai didi

c++ - 错误 : overloaded 'operator<<' must be a binary operator (has 3 parameters)

转载 作者:IT老高 更新时间:2023-10-28 21:40:27 34 4
gpt4 key购买 nike

我知道有很多这样的问题,但我找不到适合我的解决方案。

我正在尝试制作简单的分数计算器,它可以添加或减去任意数量的函数并将答案写为缩减分数。

示例:输入=3/2 + 4/8, 输出 =2

我正在尝试重载运算符以完成此操作。

所以在我尝试开发的程序中,输入由一个表达式组成,该表达式由运算符 +- 分隔的分数组成。

表达式中分数的数量是任意的。

以下 6 行中的每一行都是有效输入表达式的示例:

1/2 + 3/4
1/2 -5/7+3/5
355/113
3 /9-21/ -7
4/7-5/-8
-2/-3+7/5

***我遇到的问题是,当我运行我的程序时,它有一个重载操作错误:*错误:重载 'operator<<' must be a binary operator(有 3 个参数)****

  /Users/Spicycurryman/Desktop/ECS40/hw1/fraction.cpp:61:22: error: overloaded 'operator<<' must be a binary operator (has 3 parameters)
ostream& Fraction::operator<<(ostream &os, Fraction& n)
^
/Users/Spicycurryman/Desktop/ECS40/hw1/fraction.cpp:80:22: error: overloaded 'operator>>' must be a binary operator (has 3 parameters)
istream& Fraction::operator>>(istream &os, Fraction& n)

我不明白为什么这是一个错误。

我的以下代码如下:

CPP 文件

#include "Fraction.h"

Fraction::Fraction(int a, int b)
{

}
int Fraction::find_gcd (int n1, int n2)
{
int gcd, remainder;

remainder = n1 % n2;
while ( remainder != 0 )
{
n1 = n2;
n2 = remainder;
remainder = n1 % n2;
}
gcd = n2;

return (gcd);
}

void Fraction::reduce_fraction(int nump, int denomp)
{
this->nump = nump;
this->denomp = denomp;
int gcd;
gcd = find_gcd(nump, denomp);
nump = nump / gcd;
denomp = denomp / gcd;

if ((denomp<0 && nump < 0 ))
{
denomp*=-1;
nump*=-1;
}
else if (denomp < 0 && nump >0){
denomp*=-1;

}
if ( denomp ==0) {
throw invalid_argument( "Error: zero denominator" );
}
}



Fraction& Fraction::operator+(const Fraction& n) {
denom = denomp * n.denom;
numera = (nump * n.numera) + (n.denom * n.nump);
return (*this);

}

Fraction& Fraction::operator-(const Fraction& n) {
denom = denomp * n.denom;
numera = (nump * n.numera) - (n.denom* n.nump);
return (*this);
}

ostream& Fraction::operator<<(ostream &os, Fraction& n)
{
if (n.numera == 0)
{
cout << 0 << endl;
return os;
}
else if (n.numera == n.denom)
{
cout << 1 << endl;
return os;
}
else
{
cout << n.numera << '/' << n.denom << endl;
return os;
}
}

istream& Fraction::operator>>(istream &os, Fraction& n)
{
char slash = 0;
return os >> n.numera >> slash >> n.denom;

}

头文件

#ifndef FRACTION_H
#define FRACTION_H
#include <iostream>
#include <stdexcept>
using namespace std;


class Fraction{

public:
Fraction(int a, int b);
int fraction(int a,int b);
int find_gcd(int n1, int n2);
void reduce_fraction(int nump, int denomp);
Fraction& operator+(const Fraction& n);
Fraction& operator-(const Fraction& n);
friend ostream& operator<<(ostream &os, const Fraction& n);
friend istream& operator>>(istream &is, const Fraction& n);
private:
int denom;
int numera;
int denomp;
int nump;



};

#endif

主 CPP 文件

#include "Fraction.h"
#include <iostream>
using namespace std;

int main()
{
Fraction x(2,3);
Fraction y(6,-2);

cout << x << endl;
cout << y << endl;

cin >> y;
cout << y << endl;
Fraction z = x + y;
cout << x << " + " << y << " = " << z << endl;
}

我知道运算符是成员函数,成员函数采用隐式第一个参数,这意味着我的运算符现在采用三个参数,它可能被固定为非成员函数;但是,这在该程序中不起作用。在我的情况下,我将如何修复它以使程序正常工作?

非常感谢!

最佳答案

问题是你声明了 operator>>operator<<作为非成员函数,但定义为成员函数。

这应该可以解决该问题(但会引发另一组问题)。所以不是

  ostream& Fraction::operator<<(ostream &os, Fraction& n)
{
...


istream& Fraction::operator>>(istream &os, Fraction& n)
{
...

实现为:

  ostream& operator<<(ostream &os, Fraction& n)
{
...

istream& operator>>(istream &os, Fraction& n)
{
...

另外,请注意您将函数声明为:

friend ostream& operator<<(ostream &os, const  Fraction& n);
friend istream& operator>>(istream &is, const Fraction& n);

但定义为(因此您更改了签名):

  ostream& Fraction::operator<<(ostream &os, Fraction& n)
istream& Fraction::operator>>(istream &os, Fraction& n)

正确的方法是声明和定义为:

  ostream& Fraction::operator<<(ostream &os, const Fraction& n)
istream& Fraction::operator>>(istream &os, Fraction& n)

我只是添加更改。其余与问题相同:

class Fraction{
friend ostream& operator<<(ostream &os, const Fraction& n);
friend istream& operator>>(istream &is, Fraction& n);
// the rest is the same
};

ostream& operator<<(ostream &os, const Fraction& n)
{
if (n.numera == 0)
{
cout << 0 << endl;
return os;
}
else if (n.numera == n.denom)
{
cout << 1 << endl;
return os;
}
else
{
cout << n.numera << '/' << n.denom << endl;
return os;
}
}

istream& operator>>(istream &os, Fraction& n)
{
char slash = 0;
return os >> n.numera >> slash >> n.denom;

}

关于c++ - 错误 : overloaded 'operator<<' must be a binary operator (has 3 parameters),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23335209/

34 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com